21) In Problems 21 through 26 are given (xa)'= a xa-1, (x)' = 1, ( constant )'= 0, (sinx)' = cos x, (cos x) '= - sin x, (tan x)' = sec2 x, (cot x)' = - csc2 x, (sec x)' = Find [ x9+ 29]' 21) = sec x tan x. A) 8× B) 9x8 C) 9x D) 9(x8+1) 22) Find 16x8 . x4 22) A) 8 x B) 4x4 C) V32 x2 D) 16 x3 23) f' (x) =(3 cot x - 2 csc x)'= [ By Linear Property] 23) A) (3 cot x - 2 csc x) C) -csc x (3 csc x - 2 cot x) B) - 3 csc x + 2 cot x D) csc x (2 csc x- 3 cot x)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.4: Values Of The Trigonometric Functions
Problem 19E
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21) In Problems 21 through 26 are given (x")'= a xa-1, (x)' = 1, ( constant )'= 0, (sinx)' = cos x,
(cos x) '= - sin x, (tan x)' = sec2 x, (cot x) '= - csc2 x, (sec x)' = sec x tan x.
Find [ x9+ 29]' =
21)
A) 8×
B) 9x8
C) 9x
D) 9(x8+1)
16x8
22) Find
22)
x4
A) 8 x
B) 4x4
C) 32 x2
D) 16 x3
23) f' (x) =(3 cot x - 2 csc x)'=
[ By Linear Property]
23)
A) (3 cot x - 2 csc x)
C) -csc x (3 csc x - 2 cot x)
B) - 3 csc x + 2 cot x
D) csc x (2 csc x - 3 cot x)
24) Using Product Rule (fg)'=f'g+fg', find (x cos x)
24)
A) cos x - x sin x
B) sin x + x cos x
C) sin x - x cos x
D) cos x + x sin x
25) Using Quotient Rule -
(f'g-fg')
4x
to find
25)
g2
(100+4x)
A) (100 +
4x)-2
B) 100(100 + 4x)2
C) 400(100 + 4x)-2
D) 4(100 + 4x)-2
26) Using Using Power Rule [f(x))ª] ' = a [f(x)]a=1 f'(x) to find [(100 + 4x)3 ]' =
26)
A) 12(100 + 4x)3
B) 12(100 + 4x) 2
C) 4(100 + 4x)-2
D) 3(100 +
- 4x)2
Transcribed Image Text:21) In Problems 21 through 26 are given (x")'= a xa-1, (x)' = 1, ( constant )'= 0, (sinx)' = cos x, (cos x) '= - sin x, (tan x)' = sec2 x, (cot x) '= - csc2 x, (sec x)' = sec x tan x. Find [ x9+ 29]' = 21) A) 8× B) 9x8 C) 9x D) 9(x8+1) 16x8 22) Find 22) x4 A) 8 x B) 4x4 C) 32 x2 D) 16 x3 23) f' (x) =(3 cot x - 2 csc x)'= [ By Linear Property] 23) A) (3 cot x - 2 csc x) C) -csc x (3 csc x - 2 cot x) B) - 3 csc x + 2 cot x D) csc x (2 csc x - 3 cot x) 24) Using Product Rule (fg)'=f'g+fg', find (x cos x) 24) A) cos x - x sin x B) sin x + x cos x C) sin x - x cos x D) cos x + x sin x 25) Using Quotient Rule - (f'g-fg') 4x to find 25) g2 (100+4x) A) (100 + 4x)-2 B) 100(100 + 4x)2 C) 400(100 + 4x)-2 D) 4(100 + 4x)-2 26) Using Using Power Rule [f(x))ª] ' = a [f(x)]a=1 f'(x) to find [(100 + 4x)3 ]' = 26) A) 12(100 + 4x)3 B) 12(100 + 4x) 2 C) 4(100 + 4x)-2 D) 3(100 + - 4x)2
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