Problem: In problem 21.84 of your book, University Physics 15th edition (see End of the Chapter 12 section), what is the electric field along the x-axis at the origin? Answer: 2 E = Q/(2 a

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21.84 • CALC A semicircle of Figure P21.84
radius a is in the first and second
quadrants, with the center of cur-
vature at the origin. Positive charge
+Q is distributed uniformly around
the left half of the semicircle, and
negative charge -Q is distributed
uniformly around the right half of
the semicircle (Fig. P21.84). What
are the magnitude and direction of the net electric field at the origin
produced by this distribution of charge?
Transcribed Image Text:21.84 • CALC A semicircle of Figure P21.84 radius a is in the first and second quadrants, with the center of cur- vature at the origin. Positive charge +Q is distributed uniformly around the left half of the semicircle, and negative charge -Q is distributed uniformly around the right half of the semicircle (Fig. P21.84). What are the magnitude and direction of the net electric field at the origin produced by this distribution of charge?
Problem:
In problem 21.84 of your book, University Physics 15th edition (see End of the Chapter 12 section), what is the
electric field along the x-axis at the origin?
Answer:
E = Q/(2
a
2.
Transcribed Image Text:Problem: In problem 21.84 of your book, University Physics 15th edition (see End of the Chapter 12 section), what is the electric field along the x-axis at the origin? Answer: E = Q/(2 a 2.
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