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2(150–x2) 100+r 3x2 100- dt 300–2x2 100+1 3x2 100- dx2 di dx2 (5) (300–2x2)(100–1)–3x½(100+1) %3D dt (100+1)(100–1) 300+1 (100+1)(100–1)*2 = 300 100+r dt Consider the integrating factor for equation (5). 500+ IF =el (100+(100-0 IF = e2 In(t+100)–3 In(t–100) (*+ 100)2 In IF = e" -100) (1+100)? (1-100) IF =

2(150–x2) 100+r 3x2 100- dt 300–2x2 100+1 3x2 100- dx2 di dx2 (5) (300–2x2)(100–1)–3x½(100+1) %3D dt (100+1)(100–1) 300+1 (100+1)(100–1)*2 = 300 100+r dt Consider the integrating factor for equation (5). 500+ IF =el (100+(100-0 IF = e2 In(t+100)–3 In(t–100) (*+ 100)2 In IF = e" -100) (1+100)? (1-100) IF =

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.1: Systems Of Equations
Problem 6E
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I have a question regarding this answer, specifically at the moment it's solved the IF at step 4, because instead of doing e^∫ 300+t/(100-t)(100+t)dt, 300+t it's changed for 500+t and with that he continues the resolution of the problem.

It's correct or I'm missing something? Thanks

Consider equations (2) and (3). 2(150-x2) 3x2 100-1 dx2 di 100+t dx2 300–2x2 3x2 dt 100+1 100-1 (5) (300–2x2)(100-1)-32(100+1) (100+1)(100-1) dt 300+t (100+1)(100–1) 300 X2 D 100+1 dt Consider the integrating factor for equation (5). 500+ -di IF =el (100+(100-) IF e2 In(t+100)–3 In(1–100) (+100)2 In IF = e (-100)3 (1+100)² IF = (1-100) +
Transcribed Image Text:Consider equations (2) and (3). 2(150-x2) 3x2 100-1 dx2 di 100+t dx2 300–2x2 3x2 dt 100+1 100-1 (5) (300–2x2)(100-1)-32(100+1) (100+1)(100-1) dt 300+t (100+1)(100–1) 300 X2 D 100+1 dt Consider the integrating factor for equation (5). 500+ -di IF =el (100+(100-) IF e2 In(t+100)–3 In(1–100) (+100)2 In IF = e (-100)3 (1+100)² IF = (1-100) +
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