23. А - В + С

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.3: Change Of Basis
Problem 5EQ
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In Exercises 21, 22, 23, 24, 25, 26, 27, and 28, evaluate the given expression. Take
1 - 1
A = [
0 2 -1 5 - 1
0 - 1
1, and C = [
1
х 1 w
1.
3
1,B = [
z r
4
[HINT: See Example 4 and Quick Examples 7 and 8.]
Transcribed Image Text:In Exercises 21, 22, 23, 24, 25, 26, 27, and 28, evaluate the given expression. Take 1 - 1 A = [ 0 2 -1 5 - 1 0 - 1 1, and C = [ 1 х 1 w 1. 3 1,B = [ z r 4 [HINT: See Example 4 and Quick Examples 7 and 8.]
23. А — В + С
ANSWER I
Transcribed Image Text:23. А — В + С ANSWER I
Expert Solution
Step 1

Given,         A=1-1002-1 , B=30-15-11 , C=x1wzr4

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