23. Find the standard form of the equation. 81x -162x +36y² – 144y – 2691=0 (x-1)° , (v– 2)* - 1 [A] 36 81 (x-2)° (v-1)* - 1 [B] 81 36 (x-2)* ¸ (v-1)* [C] 36 =D1 81 (x-1)°, (y-2) =D1 [D] 81 36

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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23. Find the standard form of the equation.
81x -162x+36y² – 144y – 2691=0
(x-1)° , (v- 2)*
[A]
= 1
36
81
(x-2), (v–1)°
[B]
=1
81
36
(x-2)* , (v-1)*
[C]
36
- 1
81
(x-1)° ¸ (v-2)" -1
[D]
81
36
Transcribed Image Text:23. Find the standard form of the equation. 81x -162x+36y² – 144y – 2691=0 (x-1)° , (v- 2)* [A] = 1 36 81 (x-2), (v–1)° [B] =1 81 36 (x-2)* , (v-1)* [C] 36 - 1 81 (x-1)° ¸ (v-2)" -1 [D] 81 36
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