Can you help me step by step?
24 Find the tangent line to y 2 x^ -x+ 2 at x=2. 2 The tangent line to y x-x + 2 at x = 2 is y=
We first have to find y at x=2
y=2
у3Vx*-х+2 22-2+2 у- у34 У-2
We need slope dy/dx at x=2 and y=2
First square both sides of the given expression
then differentiat...
y=/x2-x+2 y2x2-+2 d (y2) dx dx - (x2-x+2) dy 2у -2х-1 dx dy =2(2)-1 2(2) dx dy 4 4-1 dx dy 4 =3 dx dy 3 4 dx
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