24 lim b7b+1 lim t 5 Calculate the following limits by direct substitution. (b-4)² (1 – t) (t + 5) 3t - 7 lim (6y) (y² + 1)³ -1 lim √3(x² + 12) = z 0 lin t> 6 ² + 3t - = lim y³ (5-3y²) 2 2 = = = 3

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