24. 23. 22. Given log C-x, express in term of x (a) 108m (1). logm (b) logm Cm³. Given log, 7-r, express in term of r: (a) log, 49, log, 343a². (b) Solve the equation : 1+ log2 (x - 2) = log 2x [4 marks] (Ans: 2x+6) (Ans: 2r) (Ans: 3+2 @ 3+2) [4 marks] [3 marks] (Ans: 4)
24. 23. 22. Given log C-x, express in term of x (a) 108m (1). logm (b) logm Cm³. Given log, 7-r, express in term of r: (a) log, 49, log, 343a². (b) Solve the equation : 1+ log2 (x - 2) = log 2x [4 marks] (Ans: 2x+6) (Ans: 2r) (Ans: 3+2 @ 3+2) [4 marks] [3 marks] (Ans: 4)
Chapter6: Exponential And Logarithmic Functions
Section6.1: Exponential Functions
Problem 60SE: The formula for the amount A in an investmentaccount with a nominal interest rate r at any timet is...
Related questions
Question
![25.
26.
24.
=
23.
m =
22
Given log C-x, express in term of x
-(1-1).
logm Cm³.
(a)
(b)
(b)
Given log, 7=r, express in term of r:
(a)
log, 49,
log, 343a².
logm
Solve the equation :
Find the value of x which satisfy the equation
Given logs 4 = x
Solve the equation log 64 = 2 + log₂ .x.
=
and
Y₁-2 y2-1
x1-x2
X2-X1
vertical distance
horizontal distance
2+
1+ log2 (x-2) = log 2x
vertical
distance
horizontal distance
2
log, xy
logg 80 = y. Express x in terms of y.
+
Equation of Straight Line, y=mx+c; where m= gradient, c=y-intercept
y-intercept
x-intercept
y = log10 y, X = x
2
log, xy
m = -
[4 marks]
vertical
distance
(Ans: 2r)
(Ans: 3+2 @ 3r+2)
[4 marks]
+ 8 = 5r.
[4 marks]
[4 marks]
m=-
(Ans: 2x+6)
horizontal distance
[3 marks]
[4 marks]
(Ans: 4)
(Ans : 2)
vertical distance
(Ans: 2, 1)
(Ans: x=
x=33²-4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd8f53252-2eb8-4dc2-9f8d-d02891640568%2F7a7a71b4-4a70-464b-ba40-29f3010c0428%2Flt9kvfb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:25.
26.
24.
=
23.
m =
22
Given log C-x, express in term of x
-(1-1).
logm Cm³.
(a)
(b)
(b)
Given log, 7=r, express in term of r:
(a)
log, 49,
log, 343a².
logm
Solve the equation :
Find the value of x which satisfy the equation
Given logs 4 = x
Solve the equation log 64 = 2 + log₂ .x.
=
and
Y₁-2 y2-1
x1-x2
X2-X1
vertical distance
horizontal distance
2+
1+ log2 (x-2) = log 2x
vertical
distance
horizontal distance
2
log, xy
logg 80 = y. Express x in terms of y.
+
Equation of Straight Line, y=mx+c; where m= gradient, c=y-intercept
y-intercept
x-intercept
y = log10 y, X = x
2
log, xy
m = -
[4 marks]
vertical
distance
(Ans: 2r)
(Ans: 3+2 @ 3r+2)
[4 marks]
+ 8 = 5r.
[4 marks]
[4 marks]
m=-
(Ans: 2x+6)
horizontal distance
[3 marks]
[4 marks]
(Ans: 4)
(Ans : 2)
vertical distance
(Ans: 2, 1)
(Ans: x=
x=33²-4)
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