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25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-

25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter10: Inequalities
Section10.7: Graphing Linear Inequalities
Problem 13OE
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25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-
Transcribed Image Text:25. Describe {x : x² + 2x < 3} as an interval. Hint: Plot y = x² + 2x – 3. SOLUTION The inequality x2 + 2x < 3 is equivalent to x2 + 2x – 3 < 0. The graph of y = x2 + 2x – 3 is shown below. From this graph, it follows that x² + 2x – 3 < 0 for –3 < x < 1. Thus, the set {x : x? + 2x < 3} is equivalent to the interval (-3, 1). y -x+ 2x – 3 12 10-
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