250mm 100mm 8=30° P 300mm 50mm How much force does the can crusher exert on the can with the force P= 60 N if the system is in equilibrium?
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- A square thread jackscrew has a 2 threads per inch. It is to lift 15tons. The friction radius of the collar is 1 in. The coefficient offriction between the threads of the screw and base is 0.15, thatbetween the screw and the collar is 0.13. Determine:a. The diameter of the root of the screw if theallowable stress in compression is 6 000 psi.b. The torque required to turn the screw.c. The pull required at the end of a 5 ft bar raises theload.d. The twisting moment exerted at the root of thethreads.e. The power output of the screw if it is turning at 60rpm.f. The power input of the screw.g. The efficiency of the screw and collarThe shaft, is driven by pulley B from an electric motor. Another belt drivefrom pulley A is running a compressor. The belt tensions for pulley A are 1500 N and 600 N. The ratioof belt tensions for pulley B is 3.5. The diameter of pulley A is 150 mm and the diameter of pulley B is 480 mm. The allowable tensilestress for the shaft material is 170 MPa and the allowable shear stress is 85 MPa. Taking torsion andbending factors as 1.25 and 1.75 respectively, find the shaft diameter.Also find out the dimensions for a hollow shaft with outside diameter limited to 30 mm. Compare theweights of the two shafts. [Ans. 30 mm ; 24 mm ; 1.82 Given Length CD=350mm Length AB=150mm Length BD=100mm The total length is CD =350PROBLEM: 3 A helical spring made of C50 steel has an outside diameter of 91 mm and a wire diameter of 11 mm. The spring has to support a maximum axial load of 1.25 KN. Determine the maximum shear stress and total deflection. If the springs have 14 coils with ends ground flat. Determine also the factor of safety. Take G = 0.85x102 KN/mm2.Take yield strength of C50 as 380 N/mm2.
- A damper square mat is supporting a dead load weight of8 kN. Helical springs will be used to support the loadlocated at all corners with shearing stress of 120.6 Mpaat 20 turns. The spring has a deformation of 98.7 mmwith a mean radius of 80 mm. Design the minimumdiameter of the wire to support a load. Use G = 83 Gpa.Show how to find the force needed to move the top block. Use reasonable data and use an equilibrium analysis to explain your answer.Select F1=108 and F2=112 on the train bridge in the figure. Find the force on the bar BC and whether it is the pull.
- Question 4A close-coiled helical spring is to have a stiffness of 90 kN/m and is to exert a maximum force of 3.7 kN. If the mean diameter of the coils is 80 mm, and the maximum stress is not to exceed 300 MPa, calculate the required number of coils and the diameter of the steel rod from which the spring should be made (G=80 GPa).The bridge construction company Z is facing problems with the mechanism of the crane, which it uses to lift the beams of the bridges. We have been informed that the bars are made of UNSG 10100 HR steel (Sy= 26x10^3psi, E= 30x10^6psi) and it is required that you determine the maximum weight that the system can support in order to identify what the problem is.The force P3 to make it to equilibrium in kN is The Stress in section 1 in N/mm2 is The Compressive Stress in section 2 in N/mm2 is The stress in section 3 in N/mm2 is The total change in length in x10-3 mm is
- A single-piece bicycle crank is shown below under the following load: the rider pedals forward with a vertical force Fp = 500 N on the left pedal and no force on the right pedal. The chain exerts a force Fc on the chainring. The spindle is a solid cylinder with a diameter d = 16 mm. 1. Draw a free-body diagram of the entire crankset and find the reactions at the ball bearings and the force from the chain.Hi! Help me with this please. This is under Statics of Rigid Bodies. Thank you so much! A 500-kg block is resting on a 30º inclined plane with fs = 0.30. Find the required force P acting horizontally that will prevent the block from sliding. PLEASE CORRECT ANSWER.A typical compound helical spring consists of two coaxial closed coil spring having the following particulars: Outer spring 1: mean coil diameter = 100 mm Wire diameter = 12.5 mm No. of turns = 15 Inner spring 2: mean coil diameter = 75 mm No. of turns = 20Both the springs are of equal initial length when unloaded. Ifthe working stress for each spring is to be same. The modulus of rigidity for the wire material is 80 GPa. Calculate the following:a. Diameter of steel wire for inner spring. b. Stiffness of inner springc. Stiffness of the compound spring. I need answer ASAP. Thank you!