27-30 - Finding Inequalities from a Graph An equation and itsgraph are given. Find an inequality whose solution is the shadedregion.27. y = x – 128. y = x* + 2y.y.29. x² + y = 430. y = x' – 4x

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College Algebra

7th Edition

ISBN:9781305115545

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter1: Equations And Graphs

Section1.8: Solving Absolute Value Equations And Inequalities

Problem 2E

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Sketch the region that corresponds to the given inequalities. 2x + 4y ≥ 4 2x − 4y ≤ 4 x ≥ 0 The x y-coordinate plane is given. There are 3 lines and a region labeled "solution set" on the graph. The first line enters the window in the second quadrant, goes down and right, passes through the point (−4, 3), crosses the y-axis at y = 1 crossing the vertical line, crosses the x-axis at x = 2 crossing the second line, passes through the point (4, −1), and exits the window in the fourth quadrant. The second line enters the window in the third quadrant, goes up and right, passes through the point (−4, −3), crosses the y-axis at y = −1 crossing the vertical line, crosses the x-axis at x = 2 crossing the first line, passes through the point (4, 1), and exits the window in the first quadrant. The vertical line crosses the x-axis at the origin. The solution set is below the first line, below the second line, and to the right of the vertical line. The regions…
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how to solve this problem nbr. 33 you need to find the maximum, minimum and inflexion point if there is one

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27-30 - Finding Inequalities from a Graph An equation and its graph are given. Find an inequality whose solution is the shaded region. 27. y = x – 1 28. y = x* + 2 y. y. 29. x² + y = 4 30. y = x' – 4x