27 (t +1)y" + ty' – y = (t+ 1)2, y(t) = t, y2(t) = e=t.

Calculus: Early Transcendentals
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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In 27-30, verify that the given pair of functions form an FSS for the associated homoge-
neous DE, then, working from first principles, use the method of variation of parameters
to find a particular solution y, of the nonhomogeneous equation.
27 (t+ 1)y" + ty' -y = (t+1), y1(t) = t, y2(t) = e-.
28 2ty" - (t+2)y' + y = -t2, yı(t) = t+ 2, y2(t) = et/2.
29 ty" + (2t – 1)y' - 2y = 32t e2t, y1(t) = 2t – 1, y2(t) = e-24.
30 (t – 2)y" + (1 – t)y' + y = 2(t – 1)e-t, y1(t) = t – 1, y2(t) = e'.
Transcribed Image Text:In 27-30, verify that the given pair of functions form an FSS for the associated homoge- neous DE, then, working from first principles, use the method of variation of parameters to find a particular solution y, of the nonhomogeneous equation. 27 (t+ 1)y" + ty' -y = (t+1), y1(t) = t, y2(t) = e-. 28 2ty" - (t+2)y' + y = -t2, yı(t) = t+ 2, y2(t) = et/2. 29 ty" + (2t – 1)y' - 2y = 32t e2t, y1(t) = 2t – 1, y2(t) = e-24. 30 (t – 2)y" + (1 – t)y' + y = 2(t – 1)e-t, y1(t) = t – 1, y2(t) = e'.
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