29. What is the center of the circle in the standard form (x- 6)² + (y-1)2 = 81? а. (6,1) %3D b. (-6,1) с. (6, -1) d. (-6, -1) 30. What is the radius of the circle in the standard form (x – 6)2+ (y – 1)² = 81? a 7 h 8 9 d. 10

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter1: Variables, Expressions, And Integers
Section1.8: The Coordinate Plane
Problem 2C
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_29. What is the center of the circle in the standard form (x – 6)² + (y - 1)² = 81?
а. (6,1)
%3D
b. (-6,1)
с. (6, -1)
d. (-6, -1)
30. What is the radius of the circle in the standard form (x – 6)² + (y – 1)² = 81?
а. 7
-
b. 8
с. 9
d. 10
Transcribed Image Text:_29. What is the center of the circle in the standard form (x – 6)² + (y - 1)² = 81? а. (6,1) %3D b. (-6,1) с. (6, -1) d. (-6, -1) 30. What is the radius of the circle in the standard form (x – 6)² + (y – 1)² = 81? а. 7 - b. 8 с. 9 d. 10
coordinate plane.
x² + y² = 49
Ay
Transcribed Image Text:coordinate plane. x² + y² = 49 Ay
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