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2e* 1+e-2x dx =

2e* 1+e-2x dx =

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3. The following integration can be solved by using the Substitution technique, where we have u = e^{-x} + and du = - e^{-x} dx , to get 2e-x 1+e-2x dx = D (Choose the correct letter). A. – In(e-2x + 1) + c В. tan-' (e-2×) + c C. -2 In(e¯* + 1) + c D. -2 tan-1 (e¬*) + c
Transcribed Image Text:3. The following integration can be solved by using the Substitution technique, where we have u = e^{-x} + and du = - e^{-x} dx , to get 2e-x 1+e-2x dx = D (Choose the correct letter). A. – In(e-2x + 1) + c В. tan-' (e-2×) + c C. -2 In(e¯* + 1) + c D. -2 tan-1 (e¬*) + c
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