-2л sin x dx

Q: Find the area under the curve y sin x, 0sxs%

A:

Q: Which integral corresponds to the area of the shaded region between the curves y = -x? + 3x and y =…

A:

Q: Calculate the definite integral by referring to the figure with the indicated areas. f(x)c a b Area…

A: The properties of definite integral can be used to solve the particular problem. Here the definite…

Q: Calculate the area of the shaded region, where f(x) = sin(x) and g(x) = cos(x).

A: Given that fx=sin xgx=cos x To find the area of the shaded region of the curves from 0 to 2π The…

Q: Evaluate the integral and interpret it as a difference of areas. 2 x³ dx

A: Given,   ∫-12x3dx

Q: Write a definite integral that represents the area of the region.  f(x) = cos x

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Q: se integral to find the area of B.

A:

Q: Find the area of the region bounded by y = sin? x & y = sin³ x for 0 < x < T.

A: 1/6(3Pi-8)

Q: Calculate the integral, assuming that " g(x) dx = 29. (Give your answer as a whole or exact number.)…

A:

Q: Evaluate the integral and interpret it as the area of a region. я/2 |8 sin(x) – 8 cos(2x)| dx

A: Here this is a tricky question Find where the function is positive and where the function is…

Q: What is the area of the shaded region? y = 2 2 x = TT y = 1 + cos x

A:

Q: Evaluate the integral and interpret it as the area of a region. T/2 14 sin(x) – 4 cos(2x)| dx

A: We have to

Q: Complete the table to find the indefinite integral.                                   Original…

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Q: Evaluate the integral (by interpreting it as the area between two curves) 1 æp |æ – g2| |

A:

Q: Use a definite integral to find the area of the region between the given curve and the x-axis on the…

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Q: Write a definite integral that represents the area of the region.                      f(x) = 4 −…

A: Given: fx=4-x,   -4≤x≤4

Q: Evaluate the integral by interpreting it in terms of areas.

A:

Q: Sketch the region whose area is given by the definite integral, then use a geometric formula to…

A: Answer is mentioned below

Q: Calculate the definite integral by referring to the figure with the indicated areas. Area A = 1.329…

A:

Q: Sketch the area that the definite integral represents and calculate the area geometrically (not…

A: Given the definite integral,  ∫13(x+2)dx It represents the area under the curve y=x+2  where x∈[1,3]…

Q: Evaluate the integral using FTC I.

A:

Q: Set up the definite integral required to find the area of the region between the graph of y = 13-²…

A:

Q: Which one of the following integrals represents the area enclosed by the curves y 1 and y = 2 – x².

A: Equate both curves for intersection point, then equate the integral.

Q: Find the area of each piece of the graph after sectioning off between x values. The Definite…

A: Since you have asked multiple questions in a single request, we will be answering only the first…

Q: Find the area between y = x + 11 and y = 3x + 2 between x O and x 2. %3D |3D Enter the exact answer

A: Given:       y=x+11       y=3x+2 over interval 0,2 The area between curves is the area between a…

Q: b. Write an integral to find the area under the curve.

A:

Q: Evaluate the integral | r – 3| dx by interpreting it in terms of area.

A: Formula for integrating modulus function:

Q: Write a definite integral that represents the area of the region. Y1= 3(x^3- x) Y2 = 0

A: The given equation is y1=3x3-x, y2=0. Find the definite integral that represents the area of the…

Q: Evaluate the integral and interpret it as the area of a region. •T/2 14 sin(x) – 4 cos(2x)| dx

A: Given that integral ∫0π24sin(x)-4cos(2x)dx First, we have to split integral because,…

Q: Write an integral that represents the area of the shaded region of the figure. Do not evaluate the…

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Q: Determine a definite integral that represents the area. region in the first quadrant within the…

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Q: Evaluate the integral by interpreting it in terms of areas •5 (x – V 25 – x?) dx -5

A: Given,  ∫-55x-25-x2dx

Q: Sketch the region whose area is given by the integral and evaluate it. 3x 5 dr d0 Answer:

A:

Q: y = e", y = xe and x = 0

A: The region bounded by the given curve is:

Q: Sketch the region whose area is given by the definite integral and then use a geometric formula to…

A: Given

Q: Given the area of the region enclosed by y = 2 – x´ and y =-x, identify the integral that represents…

A:

Q: Find the 1* quadrant area bounded by y² =2-x and y =x.

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: Use a familiar formula from geometry to find the area of the region described and then confirm using…

A:

Q: Write a definite integral that represents the area of the region. f(x) = tan x

A: To Determine: Write a definite integral that represents the area of the region. f(x) = tan x Given:…

Q: Evaluate the integral and interpret it as the area of a region. 6 •π/2 19 sin(x) - 9 cos(2x) dx

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Q: .2 L(x² + xy - y²) dy dx. 13.

A:

Q: Determine the integral below (j is the imaginary part)

A: In this question, we solve the integral by using the property of definite integral along with Euler…

Q: 6. Sketch the region between y = sin?(x) and y = 0 for x between 0 and r. As well, find the area of…

A: From the given curves the bounded region is as shown below:

Q: Also: Sketch the region whose area is given by the definite integral, and find the area by using a…

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Q: Evaluate the integral and interpret it as the area of a region. 4x + 5 – x dx Sketch the region.

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Q: the area bonnded by y=X y-X

A:

Q: x³e* dx

A:

Riemann Sum

Riemann Sums is a special type of approximation of the area under a curve by dividing it into multiple simple shapes like rectangles or trapezoids and is used in integrals when finite sums are involved. Figuring out the area of a curve is complex hence this method makes it simple. Usually, we take the help of different integration methods for this purpose. This is one of the major parts of integral calculus. 

Riemann Integral

Bernhard Riemann's integral was the first systematic description of the integral of a function on an interval in the branch of mathematics known as real analysis.