Question

Asked Dec 12, 2019

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2sin^{2}Θ = -2sinΘ + 3sinΘ + 1

Step 1

The given trigonometric equation is,

Step 2

Observe that the above equation is in the form of quadratic equation.

So consider *a* = 2, *b* = –1 and *c* = –1 and su...

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