Question
Asked Dec 12, 2019
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2sin2Θ = -2sinΘ + 3sinΘ + 1

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Expert Answer

Step 1

The given trigonometric equation is,

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2 sin? 0 =-2sin0+3sin0+1... (1) Rewrite (1) as, 2 sin? 0 – sin0 -1=0 Let x = sin 0. That implies, 2x – x –1=0.

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Step 2

Observe that the above equation is in the form of quadratic equation.

So consider a = 2, b = –1 and c = –1 and su...

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1+(-1) – 4(2)(-1) 2(2) х%3 х- 1+1 +8 1+3 4 4 or 4 =1 or 4)

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