2tany for (secx) - tan" ()+ e° csc"(x²) dy find dx sinx

Q: 2 sinx d x V1-2cosx

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Q: m. n. Sex: [ tan³ x dx ex sec³ ex dx

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Q: Find  the slope of the curve y=cos((pi tanx)/6) at the point where x=pi/2.

A: given,  y=cos(pi tanx)6  at x=π2

Q: aluate 4e3 tan z sec2 x dx.

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Q: find dy/dx, y=tanx-secx

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Q: COS V4- x2 dx -2 1/2

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Q: 4si 2xcos²x dx sin2xcos2x

A: It is given that,     ∫4 sin2xcos2xsin2xcos2x dx We have to evaluate it.

Q: Solve d'y dx² cot x dy - sin² sin²x.y - dx = cos x - cos³ 3 OHS X.

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Q: dy/dx= tan^2x/sec^2y when y= pie/4 and x=0

A: Given dydx=tan2xsec22y   y=π4 and x=0

Q: ) Find the nearest distance from the point (-4,2) and the line 2x - y = 5 d²y and dx dy O Find if x…

A: 1. A) given point is (-4,2) and the line 2x-y=5 B) given that x=sin3z and y=tan23z find dydx and…

Q: Find dy/dx of inverse tan(1/x) multiplied by secant(x)

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Q: dy sin(2x) Find for y || dx /3 – x2 dy dx II

A: Doing the proboem by obtaining the derivative.

Q: -3 dx L-3 x(x+1) Jo² tan x dx 5.

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Q: 4) Find the point(s) of inflection f(x)=(sinx)(e*)

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Q: Solve dy/dx=tan2(x+y)

A: To solve the equation

Q: 3. dx -x' csc 2 ydy = - dy tan 2y

A: The solution are next step

Q: find dy/dx 27. y = 4 tan (x3/3)         28. y = sec (x2 - 1)

A: ddx4tanx33Take the constant out:  a·f'=a·f '=4ddxtanx33Apply chain rule:=sec2x33ddxx33=4sec2x33x2

Q: cos2r – sin2x cos2x F(x) +C• What is Fx)? For dx= 3 cosx - sinx

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Q: find dy/dx. ƒ(x) = sin x tan x

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Q: a) Find for 5x² – x³ sin y + 5e*y = 10 dx

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Q: Ssin'x cosde 3. Sin'x cos dx

A: Given: ∫ sin3(x)  cos(x) dx We have to evaluate the given integral.

Q: Find   dy/dx.   y= (6(x^2 - 5x) /sin sq root (x)

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Q: dy/dx of y=(tan^-1 (x))^3x

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Q: Solve dy/dx =tan2(x+y)

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Q: for the equation dx ecosh-(x) = In(x) sinh-(y) Find %3D

A: Using differentiation of   product rule and implicit differentiation,

Q: dy cos-1x Find for y = dx /1-x2

A: Given :   To find dy/dx:

Q: 2x 2. Determine the derivative y' = dy/dx for the function y (sinx)" %3D

A: The function is given by y = sinx2x                         .........(1) To evaluate : The…

Q: Find for y = tan(x) dy dz2

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Q: Find dy dx 2. y tan-¹(csch x³)

A: Given y=tan-1 (csch  x3 )

Q: Find by implicit differentiation. dx 5 + 3x = sin(xy²) %3D dy Answer: dx II

A: 5+ 3x = sin (xy2)

Q: find dy y = tan-1(ex2)

A: The given equation is y=tan-1ex2. To find the value of dydx. Solution: y=tan-1ex2 differentiate with…

Q: Evaluate dy/dx if y = (sec2x - tan2x)/(2cos2x-1)

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Q: Find dy/dx by implicit differentiation. tan-1(4x2y) = x + 2xy2 y' = %3D

A: Given equation : tan-1(4x2y)=x+2xy2

Q: Q5// Evahate dx 1- J- V&r-x 6co(3x2) dx dx sin - sinx

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Q: dy dx 16. -x tan (y-x) = 1.

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Q: dy/ dx sinx=y cosx +sin²x

A: see 2nd step

Q: 1- find dy/dx as a function of x. y = sec (tan x)

A: As per bartleby guidelines for more than one questions asked only first should be answered. Please…

Q: Find dy/dx: y = (sec x)^2 - (tan x)^2

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Q: ) y= tanx+ sin x 0<x<27 (k) y=sinx -2n Sx< 2n

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Q: 1-cosx 10. Find , if y = dx 1+cos x

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Q: Find dy/dx if sin-(4y²) = 8x² – 5y3 Answer: Find dy/dx if tan- (xy²) = 3x² – 5y² Answer:

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Q: a²-x2 6- Sº, S dy dx -Va2-x2 7- Sx? cos 5 x dx

A: As per bartelby guidelines we have permitted answer only one question if given more than one…

Q: e) y=sin(tanx) f) y = sin³ 7x

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Q: Find dy/dx by implicit derivation. If tan-1(x2y) = x + xy2.

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Q: cos2x – sin2x cos2x F(x) +C. What is F(M)? For dx%3D cosx – sinx 3

A: A detailed solution is given below

Q: find dy/dx. g(x) = (2 - x) tan2 x

A: Given:

Q: ) Find (dy/dx) for: tan-¹(x² + y) - eln(x³y) = 5sinh(y)

A: We need to find dy/dx.

Q: Find dy/dx by implicit differentiation. tan-1(4x2y) = x + 3xy2 y' =

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Q: (2xy – tan y)dx + (x² – x sec² y)dy = 0

A: Solved below