Related Calculus Q&A
Find answers to questions asked by students like you.
Q: In the given equation , select the basic integration formula you can use to find the indefinite…
A: Click to see the answer
Q: Select the basic integration formula you can use to find the indefinite integral, and identify u and…
A: Click to see the answer
Q: |-7 – 9x| = 2
A: NOTE: Refresh your page if you can't see any equations. . apply absolute rule
Q: -1 A = -2 6. :)-
A: Click to see the answer
Q: у" - 2у" — Зу %3D0
A: To solve the given differential equation, first we will find the roots of Auxiliary equation and…
Q: у" - 2у" — Зу %3D0
A: Click to see the answer
Q: - 4x, =-10 X, +3x, = 2 3x, + 5x, +8x, =-6 2x,
A: We solve this system with explanation method.
Q: -4 y' = 3+2x 4
A: Click to see the answer
Q: - 2x + 3 + 4 = 0
A: The given absolute value equation is -2x+3+4=0
Q: -2z, + 3z2 + 473
A: Polar form of complex number: The complex number z = x + iy is z = rcos(θ) + i sin(θ), where r = x2…
Q: Simplify
A: Given equation is (-3x-2)(4x4)
Q: (-2x)³ 10. 8x°
A: Given that, There is a fraction following, (-2x)38x0 We have to simplify this fraction.
Q: 1) -4sx-4 <-3
A: Since you have asked multiple question, we will solve the first question for you as per our guide…
Q: Find product. (3x - 5)(2x + 1)
A: Click to see the answer
Q: 2x-323
A: Click to see the answer
Q: Find the inverse of each of the following matrices.
A: Click to see the answer
Q: -6 x- 3 OK 2- 2.
A: our objective is to find the solution
Q: -4 12) (2x²)*
A: Click to see the answer
Q: + -4 12) (2x²)
A: Click to see the answer
Q: find the most general antiderivative or indefiniteintegral. You may need to try a solution and then…
A: ∫2x3-5x+7dx=2∫x3 dx -5∫x dx +7∫dx [ ∫xn dx=xn+1n+1…
Q: Integration review Evaluate the following integrals.
A: Given Data The integral function is ∫01dp4-p. Let, p=addpp=ddpa12p=dadpdp=2pda=2adap=a0a0=0a1=1=1
Q: -2 . -2 -3 メ-
A: dxndx = n.xn-1
Q: Solve the inequality, and express the solutions in terms of intervals whenever possible.
A: Solve the inequality, and express the solutions in terms of intervals whenever possible.
Q: 2x + y = 12 3x + 2y = 16
A: Given: 2x + y = 12 3x + 2y = 16
Q: -3+6x-2x-7
A: Click to see the answer
Q: Improper integrals Evaluate the following integrals or state that they diverge.
A: Click to see the answer
Q: -10(x-7)– 7(x+ 2)
A: i -10x-7-7x+2=-10x-10-7-7x-72=-10x+70-7x-14=-17x+56
Q: -10(x- 7) – 7(x+2)
A: The given polynomials are, a) -10(-8x+9)-8xb) -10(x-7)-7(x+2)
Q: Multiply (1/3sqrtx-3/2sqrty)^2
A: To multiply
Q: Solve the inequality, and express the solutions in terms of intervals whenever possible.
A: Solve the inequality, and express the solutions in terms of intervals whenever possible.…
Q: Find product. (2x + 5)2
A: Click to see the answer
Q: S (3x412x-15)호 2dx
A: Given, ∫23x2+12x-1512dx
Q: -2/5x + 4=19
A: We have to solve
Q: х-1 1- 3x-1 3-
A: Given, 1-1x3-1x=x-1x3x-1x
Q: 2. Determine where -x* + 6x2 < 5.
A: Click to see the answer
Q: Multiply: (7x - 6y)(3x - y).
A: Click to see the answer
Q: -1 2TEX +2
A: We have to the given limit using L hospitals rule
Q: х*- 81 Find Ltx3 2 2x - 5x – 3
A: Click to see the answer
Q: (- 5x-6)(6x-30)=0
A: Click to see the answer
Q: = V 64 - x2
A: Click to see the answer
Q: Multiply: (2x + y + 3)2
A: 2x+y+32
Q: -5(2t-3)+4t=2t-2
A: Answer is 17/8 Explanation is given below..
Q: Find the value of 2x if 2x-y=6 and x+3y=30
A: Equations are 2x-y=6 ...(1) x+3y=30 ...(2) To find: 2x
Q: Multiply: (3x + y + 1)2
A: Click to see the answer
Q: Expand The equation ,2,3) and Simblify nohen
A: An expression in a variable can be expanded by substituting all the possible values o the variable.…
Q: Simplify -28x2y5/4x4y.
A: -28x2y5/4x4y
Q: Find fcx) -3 42
A: Click to see the answer
Q: Evaluate 6x ÷ 3y if x = 10 and y = 2
A: Given, 6x3y We have to evaluate 6x3y if x = 10 and y =2
Q: Give a formula for a function y = ƒ(x) and shows the graphs of ƒ and ƒ -1. Find a formula for ƒ -1…
A: Given function is fx=x2-72. Compute the inverse function. fx=x2-72y=x2-72x=y2-72y=2x+7f-1x=2x+7
Q: Differentiate: ?(x)=2xsinxtanx
A: Topic- differentiation
