2x-1 Bx + C Dx +E In x (5x2 +1)2 5x +1 (5x + 1) alter clearing fractions to decompose, the equation 2x-1=A (5x2? +1) + (Bx+ C)(x) (5x? + 1) + (Dx + E)(x) results. If x 0, what is the value of A? The value of A is (Simplify your answer Type an integer or a simplified fraction.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section9.1: Systems Of Equations
Problem 31E
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2x-1
A
Bx +C
Dx+E
In
x(5x² +1) x
5x? +1 (5x2 + 1)2"
after clearing fractions to decompose, the equation 2x-1=DA(5x2 +1)+(Bx+ C)(x) (5x2 + 1) + (Dx+ E)(x) results. If x 0, what is the value of A?
The value of A is
(Simplify your answer. Type an integer or a simplified fraction.)
Transcribed Image Text:2x-1 A Bx +C Dx+E In x(5x² +1) x 5x? +1 (5x2 + 1)2" after clearing fractions to decompose, the equation 2x-1=DA(5x2 +1)+(Bx+ C)(x) (5x2 + 1) + (Dx+ E)(x) results. If x 0, what is the value of A? The value of A is (Simplify your answer. Type an integer or a simplified fraction.)
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