(2x - 3) dx 2021 (2021– 25x25 + 25x2021) dx b. а. 4 -2021

Q: 2x-5 dx 73

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Q: -12 1. ("(25x – 46x + 3)dx -12

A: topic- definite integral if f(x) is a odd function∫-aaf(x)=0

Q: 3x2 – 4x + 3 -dx 8x3 – 6x2 – 17x + 15) -

A: The integral function is ∫3x2-4x+38x3-6x2-17x+15dx.

Q: [2x] dx -1

A: If given  Integral can be solved using fundamental theorem of calculus.

Q: d(-2x-1+ 6x7) -2 4x dx (3x5 + 4x) d dx 15x* + 4 3 d 16x dx 1 2 2

A:

Q: √² (5x²-3x+18) dx 9x - x³

A: Integration is done by dividing polynomial.

Q: 2x dx V5 + 4x – x²

A:

Q: 6x dx 3

A:

Q: -dx +5 3.

A: integarting   let subsitution  methood

Q: 5x2-12 х-12 dx х3-4х

A: Given: ∫5x2-2x-12x3-4x

Q: Evalvate 5x-12 X (x²+4) dx

A:

Q: 4x² + 5 -dx 3

A: Given, integral is

Q: 5. (3x-17) dx / (x² - 6x + 10) 11

A: As per our guide lines we are supposed to answer only one question. Kindly repost other questions as…

Q: : Evaluate: 2x³-4x²-x-3 dx х2—2х-3 |

A: we have to evaluate the integral by using partial fraction

Q: -| Vx³ + 16x² dx

A: Let I=∫x3+16x2 dx I=∫xx+16 dx Let assume x+16=t2⇒dx=2t dt I=∫(t2-16)t(2t) dt =2∫(t4-16t2)dt

Q: Vos-x 4 64 – X -dx

A:

Q: x* - 2x2 +3 dx 31 Vx2

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: V9 - x dx -3

A: Given: I=∫-339-x2dx for finding given integral we will given below property…

Q: xii. dx -x4 V3-2x-

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Q: 3x2-9x-34 1. S- dx x2-2x-24

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Q: 2x ²-11)dx x3+3x²-4

A: To evaluate the integral.

Q: 2 (3x- 2) dx Вх — -2

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Q: x-4 -dx x² – 5x +6

A:

Q: (x2 - 4x + 4)4/3 dx -

A:

Q: (4x2-3х+6)dx х (х-2)

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Q: 5x - 3 √(x+ - 4x³ + 14x² - 20x + 25) - - dx

A:

Q: evaluate the integral.

A:

Q: 4x2 + 21x + 54 -dx x² + 6x + 13

A: Given,            ∫4x2+21x+54x2+6x+13dx

Q: csc–xdx =2 csc-x.-dx 2 2

A:

Q: (2x2-x+6)dx (х2—х-2))

A:

Q: (5x-3x²+7x-3 dx (x²+1)²

A: Given,          ∫5x3-3x2+7x-3x2+12dx

Q: 4x-2 dx 27x-8

A:

Q: x-3 dx (2x–10x+13) /10x²–42x+45

A: To evaluate the given indefinite integral.

Q: 2x + 3 -dx. x2 + 3x + 4

A: To evaluate the integral: ∫2x+3x2+3x+4dx Evaluating the integral. Let substitute t=x2+3x+4…

Q: 6 x -dx („² + 1 ) (2x - 2)

A:

Q: dx Integrate: /16-9x²

A: Answer and explanation is given below...

Q: 12 -6x dx 15

A: We are asked to solve the indefinite integral. The solution of the integration is as follows:-

Q: 2x° dx x2-4

A: ∫2x3x2-4dxSubstitute u=x2-4→dudx=2x→dx=12xdu=12∫u+4udu=4∫1udu+∫1du

Q: 2 dx xVx ² -1

A: We know that the ddxarc secx=1xx2-1then∫1xx2-1dx=arc secx

Q: xlnx-x dx. (Inx)3

A: We have to find the integral

Q: La (x3 – 2x)dx -2

A:

Q: dx J-25a2 1–25x² -25x2 8.

A: The objective is to evaluate the integration.

Q: V4.x2 – 9 -dx

A: Solution of question is written in below steps.

Q: iii) 4x - 11 dx x3 - 9x2

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Q: (3x-1) dx 2x²+2x+3

A:

Q: SV2*- 16 dx 2.x

A: Consider the integral: ∫e2x−16dxApply u…

Q: -5x dx А. 3 V2x2 – 1

A: Since you have asked multiple questions in single request.so we will answering only first question.

Q: Sa4-2x3)5(4x3- 6x²) dx

A: