11-15 Given a quadratic equation, write in standard form and then substitute the values of a, b, andc into the quadratic formula. Solve the equation by using the quadratic formula.2x - 3x -5 = 011. Subsitute a, b, and c into the quadraticChoices for 11-20:formula.11-2+y(2)° – 4(3)(5)A) x =3BD) x = --1012. Solve for x.102(3)3+ (-3)' – 4(1)(5)B) x =3+ /29BE) xx²- 3x =-5102(1)13. Subsitute a, b, and c into the quadratic3+ (-3) – 4(5)(-1)C) x =formula.CD) x =-1,-2(5)14. Solve for x.-3+ (3) – 4(2)(5)D) x =3CE) x = 1,2(2)3x +2 = 5x-3± V(3) - 4(5)(1)E) x =1ABC) x = --V14-15. Subsitute a, b, and c into the quadratic2(5)formula.5+ (-5) – 4(3)(2)ABD) x =,116. Solve for x.AB) x =2(3)-5+ V(5) – 4(2)(3)5x = 3x +1AC) x =ABE) x =-1,32(3)17. Subsitute a, b, and c into the quadratic3+ (-3) – 4(2)(-5)formula.AD) x =ACD) x = -1,-2(2)18. Solve for x.5+(-5) – 4(2)(3)3土V29AE) x =ACE) x =2(2)2x - 5x+3=03+ V(-3) – 4(1)(-5)V11BC) x =ADE) x =19. Subsitute a, b, and c into the quadratic2(1)formula.20. Solve for x.GSE Algebra IIA Week 3Page 18 of 24

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Answered: 2x -3x -5=0 11. Subsitute a, b, and c…

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2x -3x -5=0 11. Subsitute a, b, and c into the quadratic formula.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter9: Quadratic Functions And Equations

Section9.6: Solving Quadratic Equations By Using The Quadratic Formula

Problem 15CYU

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Question

11-15

Given a quadratic equation, write in standard form and then substitute the values of a, b, and
c into the quadratic formula. Solve the equation by using the quadratic formula.
2x - 3x -5 = 0
11. Subsitute a, b, and c into the quadratic
Choices for 11-20:
formula.
11
-2+y(2)° – 4(3)(5)
A) x =
3
BD) x = --
10
12. Solve for x.
10
2(3)
3+ (-3)' – 4(1)(5)
B) x =
3+ /29
BE) x
x²- 3x =-5
10
2(1)
13. Subsitute a, b, and c into the quadratic
3+ (-3) – 4(5)(-1)
C) x =
formula.
CD) x =-1,-
2(5)
14. Solve for x.
-3+ (3) – 4(2)(5)
D) x =
3
CE) x = 1,
2(2)
3x +2 = 5x
-3± V(3) - 4(5)(1)
E) x =
1
ABC) x = --
V14
-
15. Subsitute a, b, and c into the quadratic
2(5)
formula.
5+ (-5) – 4(3)(2)
ABD) x =
,1
16. Solve for x.
AB) x =
2(3)
-5+ V(5) – 4(2)(3)
5x = 3x +1
AC) x =
ABE) x =-1,
3
2(3)
17. Subsitute a, b, and c into the quadratic
3+ (-3) – 4(2)(-5)
formula.
AD) x =
ACD) x = -1,-
2(2)
18. Solve for x.
5+(-5) – 4(2)(3)
3土V29
AE) x =
ACE) x =
2(2)
2x - 5x+3=0
3+ V(-3) – 4(1)(-5)
V11
BC) x =
ADE) x =
19. Subsitute a, b, and c into the quadratic
2(1)
formula.
20. Solve for x.
GSE Algebra IIA Week 3
Page 18 of 24

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