2x2-3х-1 -dx (x²+9)(x-5) E. Integrate:

Q: Vx 3 1- evNīdy dx - 3 y3 e*y dx dy

A:

Q: Ssin" x 14 x cos' x dx Integrate:

A: Given,        ∫sin14xcos5xdx

Q: Inx dx, 2. Integrate (1) using the substitution u = In x (ii) using integration by parts.

A: Integration by substitutions and by parts

Q: The integrating factor of y= 2x' is dx

A:

Q: SOLVE USING INTEGRATING FACTOR 4. (4x2 – 4xy + 3y² + 2) dx +x (2x – 2y + 1) dy = 0

A: Given, ∫(4x2-4xy+3y2+2)(-2x2+2xy-x) dx                                     ⇒−∫ 4 x2 + 4 y x − 3 y2−…

Q: 15) S 3x (x³-1)² dx

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Q: 2. (3x-y-4)dy -(x+y-4)dx=o

A: Given :

Q: 18 dx Integrate using trig. Substitution: S- x² V9– x²

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Q: Find the general solution of dx -3 y=2cos3x . dx

A: The given differential equation is. d2ydx2+2dydx-3y =2cos3x This can be written as, D2+2D-3y=2cos3x…

Q: Apply the application for integration dy/dx=2x+3 y(1)=2

A: Given: dydx=2x+3, y(1)=2

Q: Jay ti dx dy Compute the integration

A:

Q: Evaluute the integra dx 0 16+49x2

A: Here we have to evaluate I=∫-∞∞dx16+4x2

Q: Only I method. Except Exact DE (x+2y-1)dx+(2x+4y-3)dy oo

A: First we campare the given differential equation Mdx+Ndy= 0 and then solve it.

Q: The integration of dx is 4+x²

A: The given integral ∫dx4+x2 can be evaluated as, ∫dx4+x2=∫dxx2+22                =12tan-1x2+C…

Q: EXERCISE 1 dy -dx = 0

A:

Q: e dx 1- e2x (integration by substiution)

A: NOTE: Refresh your page if you can't see any equations. . ...............(1)

Q: find the integrating factor (x+1)dy - (2y+2x+1)dx = 0

A:

Q: What is the integrating factor of 2 (y – 4x2) dx + xdy = 0 72 2x

A: Solve for integrating factor

Q: What is the integrating factor of 2 (y – 4x²) dx + ædy = 0? | Oe O 2r

A:

Q: dx (2х — 5)10 Integrate -

A: We have to solve the given integral : ∫x(2x-5)10 dx = ?

Q: (y5 – x²e») dx dy -11-3

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Q: x'dx √√x(1-x)

A:

Q: x +1 -dx x² (x – 1) (a) Integrate

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Q: 8. dx +x2 Integrate:

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Q: Integrate: ∫ 3cos(2πx) dx

A: The given integral is ∫ 3cos2πxdx.

Q: 4. Evaluate e*dx using integration by parts.

A: Explanation and solutions is given below.....

Q: (b) Evaluate f 3æ“ In6x dx using integration by parts.

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Q: 23-4x-8 Integrate: 2E+4) dx 1)(r²+4)

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Q: dy -: y = 6x² – 4x, dt dx = 7,x = -2 dt (5) Find -

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Q: (a) Evaluate xe* dx using substitution method. (b) Evaluate | 6xe* dx using integration by part…

A: We will find out the required value.

Q: b) y = [ dx Integrate. 13 +5

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Q: dx 62 + x² Integrate:

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Q: find the integrating factor of (y² - x ) dx + 2ydy = 0

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Q: Solve using the integrating factor by inspection  (2x²y - y²x + yx) dx + (3x³ - 4x²y + 3x²) dy = 0…

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Q: Integrate dx/(x+1)(x^2+16) from 0 to 1

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Q: Paragraph 12) S, dx Sx+7

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Q: Integrate f dx using integration by parts. x+1

A: Please refer the attached image for complete solution.

Q: 1. Integrate: dx x2+7x+6

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Q: Solve simultaneous equation dx/dt=2x+3y , dy/dt=x+4y , x=-3 , y=1

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Q: Find the intergral of i. SVīdx ii. (x - 1)dx

A: According to Bartley guidelines I have, to solve only first question so repost the problem for…

Q: Find dy/dx by implicit differentiation. 2) x3 - 2y2 = 1 4y B) x2 + 1 A) 4y C) 2y D) x2

A: solve the following

Q: - 1) (2r + 1)½ (4x – 1) dx Perform the Integrations

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Q: Geberal solution of (3xy +3y - 4)dx+(x+1)²dy

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Q: Integrate J dx X(x-3)

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Q: (2x+ 3y) dx + (3x-y+5) dy

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Q: Evaluate / e*cos(x)dx using integration by parts-

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Q: (In x) dx Integrate: 1

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Q: x e* dx

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Q: (B): Find the integration by using substitution method √x√2x-1 dx

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Q: (b) Integrate x-³e-l/a², dx

A: Here we can find the answer as below.