Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Match column B with the correct answer on column A, write only the capital letter of the answer on the blank provided at the left side/right side of the test paper. Match from column A the solution of the differential equations on column B.
Column A
A. xlnx + ylny = c
B. 2y = x4 + cx2
C. e(x^2) + y2 = c
D. x2 = cy3
E. x2 y = 2x4 + c
F. ylnx + xlny = c
G. x2 (x2 + 2y2) = c
H. x (y + x2) = c (y – 2x)
I. xy2 – x2y + 3x2 – 2y = c
J. xy3 = 2y2 + 4y + 4 + cey
K. y (x2 + c) + 2 = 0
L. (y – x) (y + 3x)3 = cx3
M. x2 y = 2x2 + c
N. x (y + 1) = (1 + cx) ey
O. e(-x^2) + y-2 = c
P. (y + x2) = c (y – 2x)
Q. x2y2 + 2xy – x2 = c
R. x4 = c2 (4x2 + y2)
S. x2 (x+ 2y) = c
T. x2 + y2 – 3xy = c
Column B
- 2y dx = 3x dy
- (y2 – 2xy + 6x) dx – (x2 – 2xy + 2) dy = 0
- 2(y – 4x2) dx + xdy = 0
- y' = xy2
- (xy2 + y – x) dx + x (xy + 1) dy = 0
- (x – y) (4x + y) dx + x (5x – y) dx = 0
- xy3 dx + e(x^2) dy = 0
- y dx + (3x – xy + 2) dy = 0
- 2 (2x2 + y2) dx – xy dy = 0
- (x2 + y2) – xy dy = 0
- (2x – 3y) dx + (2x – 3x) dy = 0
- x2 yy’ = ey
- (x4 + 2y) dx – x dy = 0
- (3x2 – 2xy + 3y2) dx = 4xydy
- (1 + lnx) dx + (1 + lny) dy = 0
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