3-{( 3 t5 – 2 t³ + 4 e-8t)

Q: 2e-u²+2 +2 dydz. 1

A: We have to evaluate the integral ∫01∫1u2e-u2+2dydz

Q: tHons algebraically. 2. 3x - y = 4 2x + y = 11

A: Given, The system of equations  3x-y = 4  2x+y = 11  We have to solve the system of equations…

Q: max z = 4x1 + x2 s.t. 8x1 + 2x2 < 16 5x1 + 2x2 < 12 X1, X2 2 ()

A: LINEAR PROGRAMMING PROBLEM: BY graphical method

Q: 51. y = 3x + (V3 – 5): and y = -J3x + (-/3– s)

A:

Q: 2.x - y-z = 0 5x - 2у +2: 3 Зх + у - 2: -8

A:

Q: 2x+4 %3D の 4 6. %3D 41-

A: Solution is given below:

Q: -5r2 -2r3 +4r5 -2r6 %3D -#4 +5xs +5xg = -522 -8rs +4r6 = 22 +s +t tu 240

A:

Q: T : R² → R³ -3x1 + x2 (:) 3x2 x2 2x2 Ex: 5 : 5 T Ex: 5 -1 Ex: 5

A:

Q: lim, (27x - 8)(3x² – 2x)-1 ズ→ O 18 0. -9 9 /3

A:

Q: 2x+3y -2 = 4 3X++22= 13 X+ 2y-s2=-

A: Since you have asked multiple questions in a single request so we will be answering only first…

Q: v = (z* – 2z + 1)ž

A:

Q: 4 9 5- .2 13) =D1 7 2+-+ X x²

A:

Q: 2- -6 -54-3 -2 -1 2 3/4 5 6 -2 f(x) = %3D

A: We have to find out

Q: dz = z2-25

A:

Q: 18. y = -- 2x - 4 7x +y 2 19. y = x + 6x x-y= 4 20. y = x + 4r – 15 y 25 x

A:

Q: 0- V5 – x – V5+: -

A:

Q: Find (1s/(s²+4)} by convolutions

A: Given inverse Laplace transform

Q: Min Z=2X,+ X2 S.t X,+3X2 >,30 -4X1-2X2 S-40 4X,-2X2

A: See the attachment

Q: 7) y"+4y+20y-23sint-15cost y(0)-0, y'(0)--1

A: We have to solve given problem:

Q: Determine L-1 1 s²-3s-4 (s-3)(s-1)².

A:

Q: Q2: Rationalizing: 1. 8. 3/2 2. 3 5 + /6 3. V7 - 3 4

A: We’ll answer the first question since the exact one wasn’t specified. Please submit a new question…

Q: Ay 2- X -2-

A: The given graph is:

Q: y" + 4y = -5, y(T/8) = -, y'(T/8) = 2 У(п/8) - У(п/8) — 2

A:

Q: 5. 1 Z+₁ 3z 2 dz

A: Topic = Integration As per guidelines , At a time only one question can be answered. please repost…

Q: (а-2)а+1 а?-1 4. (а-1)а-2 (а-2)а+(а-2) x2-x-20. (x2-x-2 х2-х-2 ズ+1

A: Given is the expression (a-2)a+1(a-1)a-2÷a2-1a(a-2)+(a-2)·a+6a+1 We need to simplify the given…

Q: $. 12-1 (2²+-)(2-2) 1-4z+6z² 1 -dz .d

A: note : As per our company guidelines we are supposed to answer ?️only the first question. Kindly…

Q: 4. Find L-1 [ 2s-3 s2-3s+2.

A: To evaluate : L-12s-3s2-3s+2   2s-3s2-3s+2=2s-3s-1s-2                                    (1) Using…

Q: (8) lf (a-b-a) za 2b 29 (b-a-c) 2b = K²(a+b+c) ³ 2C (c-α-b) then K=

A: Given:a-b-c2a2a2bb-a-c2b2c2cc-a-b=ka+b+c3    .............1We need to find the value of k.

Q: 5- A. 3. C. +X+ P 上一站 -- V -4x 一 --年 -c + c -c

A: Topic:- integration  Note :- as per our guideline if more than one question uploaded than only first…

Q: 2s Use Convolution to find L-1[- (s²+4)2-

A: Given: L-12ss2+42

Q: - -X-4-z=4 2X- 2X+G-3z=- X 0-42=3

A:

Q: -x - y = -13 -x + 3y = 19

A: Here is given two linear equations;   -x - y = -13 -x + 3y = 19    To solve it; Put    -x=y-13…

Q: max z = 3x1 + x2 s.t. 2x1 + x2 < 6 X1 + 3x2 < 9 X1, X2 2 ()

A:

Q: 21. y = 2 + 3 sec(2x – 7)

A: sec(2x-π)=sec(π-2x)=-sec(2x)

Q: 44) (2x2) . 3x' = 8x 3 K 24h 46) (2p¬)" . 3p²) -K\GRX 230 28 46x 248 48) (2n1 n²)-1

A: We have given some expressions and we have to simplify these expressions…

Q: - 6х -Зу +5z 50 —Зх -2у -4z бх -3у —4z -34 = X = y = z =

A:

Q: T12 7. 6x- 3 > 15 or 3 + 7x 3

A:

Q: 7 If X = 5.5 4 -1 3 -V2 2 Find X-1

A: We will find out the required matrix.

Q: -V4-x² c3-x²-y² xdzdydx, -5+x2+y2

A:

Q: g(x) = -13 – x| + 5 -6- -10 -9 3 10 -1- -2- -3-

A: The objective of the question is graph the given equation.

Q: 1) y = -x + 3 and y= 2x- 6 5. 4. 3. -6 -5 -4-3 -2 -1 0 1 2 3 4 5 6

A:

Q: 2. S(-18z +36)( - 2z - 4) dz

A: We need to evaluate the following integral ∫-18z+36-2z-4dz Formula Used: ∫zndz = zn+1n+1+C

Q: e2z dz 1.9리=4z(z2-1)

A: from Cauchy residue theorem we can solve this question

Q: Q2/ Evaluate (B8-5}sec² /3(38-5)2–7 V3(30-5)2-7

A:

Q: 3) y=--x - 1 | 1 y =-x-4 4 Ay 5 4 3 -2 -2 -3 Answer:

A: follow the  next step

Q: b) Show that Δ2y0 = y2-2y1 + y0.

A: We have to show that Δ2y0 = y2-2y1 + y0.

Q: How does k^2 (-uv) become (I-k^2)?

A: The cross product of two vectors takes the opposite sign when the order is changed. u×v=−v×u…

Q: 12. (2a² – 3a) + (5b – b²)+ (2a – 8b) 14. (3x – 2)-(5x-4)+(19+2x) 16. (6m² +7)-(-2m²)+(2m – 3)

A: