3 and y=X %3D 2

Q: Determine the area of the shaded region. y= V1 – x y = %3D

A:

Q: 4. Determine the area of the shaded region. -y =Dx y= x²2

A:

Q: Find the area of the shaded region            ,  x  = 2y - y 2    , x = y 2  - 4y ,   (-3 , 3 )

A:

Q: Find the area of the shaded region. y = x3 - 4x <3,15) 3 A) 33 B) D)

A: We will solve the problem.

Q: Find the total area of the shaded region. y = 4 2- y=4 cos2x 1/2 31/2 2.

A: Area between two curves can be found by integration as shown in next step

Q: Find the area of the shaded region. y = x 4-32 40 y=x4

A:

Q: Find the area of the shaded region. y 8 y= 5 x – x 6. (3, 6) 4 2 y= 2 x X -1 4 5 2.

A:

Q: Find the area of the shaded region below. y x = y² – 4y (-3, 3) x = 2y – y²

A: We have to find the area of the shaded region.

Q: Find the area of the shaded region 1 y = x2

A:

Q: Find the area of the shaded region. y 3 y = Vx 11, 1) x = 27 1 y = 10 15 20 25 2.

A:

Q: y 4 A y = 4* 3 2 y = 2* 0.5 1

A: Given query is to find the area of shaded region.

Q: Find the total area between the region and the x- axis. y = x3 – 3x? + 2x -1 sxs2

A: Consider the curves, y=x3-3x2+2x  ;       -1≤x≤2

Q: (b) Find the total areas of the shaded region. y = x} y = -2x4 2.

A:

Q: Find the total area of the shaded region. Ay 10 Q 6- y = 5 y=x y= 2- 20 10

A:

Q: What is the area of the shaded region? y = y = -2x*

A: We will take difference of both curves to find the area using integration.

Q: b. Find the total area of the shaded region in Figure Q6b. y=(x+2)° T x+2 -13 -1 -0.3 0.3 Figure Q6b

A:

Q: X = y 12 x = 216 / y? 12

A: Given curves are x=y   ...1x=216y2   ...2

Q: Find the area of the region below y = x² + 2x 4 and above y = 3 for 2 < x < 5. %3D Area

A: Recall:            Area=  ∫abf(x)-g(x)dx  We have, f(x)=x2+2x-4, g(x)=3, a=2, b=5

Q: Determine the area of the shaded region. - y = y = V1 - x

A:

Q: Find the area of the shaded region. y (1, Зе) 8 6- y = 3 e* 4 2

A: We have given curves y = 3xex^2 and y=3ex And we have to find the area of shaded region

Q: Find the area of the shaded region. y=2x2+x-6 y=x2-4 W

A:

Q: 9. y. x = 2y x = y? – 3

A:

Q: Find the area of the region below y = x² – 2x + 5 and above y 3 for 2 < a < 5.

A: To find area under the curve Shown below in shaded part

Q: Find the area of the shaded region. y = +3 (0,3) (2,7) A) 25/3 B) 352/3 C) 26/3 D) 22/3 2 x

A:

Q: Shade the area of the region bounded by, x² + y? p

A:

Q: Find the total area between the region and the x- axis. y = x3 – 4x ; -2<x<2 -

A: Given: y=x3-4x The graph of the given function is,

Q: Find the area of the shaded region below. у y =Vx 2 x=2 1 y=- x1 Area

A:

Q: Find the area of the shaded region. y y= xV4 x y=0 2 y= 0 -2 SQuare units 21

A:

Q: Find the area of the shaded region. y = x2 + 3 (2,7) (0,3) 23 A) 3 26 В) 3 22 25 D) 3

A: As per the guidelines we can solve 1 problem only.

Q: Find the area of the shaded region. y X = y 6 x = 27 / y? 6

A: *to find:- Area, A under the closed region. *concept:- take horizontal elemental strip of length dx…

Q: Find the area of the shaded region. y 4 y= 1F1, 1) X = 27

A: Introduction: The evaluation of the area bounded by the curves and the coordinate axis is the most…

Q: Find the area of the shaded region. y 15 y = 7x-x² 10 (5, 10) 5 y= 2 x 4 6. Enhanced Feedhaclo

A: We can application integration in order to solve the given problem.

Q: Find the area of the region below y=x2−x+2 and above y=3 for 2≤x≤6. Area =

A: The objective is to find the area of the region.

Q: Find the area of the region below y = x2 – 4x + 12 and above y = 4 for 2 < x < 5. Area =

A:

Q: y = x(x2 – 4)

A: We have to find the area of the shaded region.

Q: Find the area of the shaded region. y=2 y= 2sin(70x) -2. O 4+4 4 + 8

A:

Q: Find the area of the shaded region. y y = x 2 11, 1) X= 27 1 y= 5 10 15 20 25 3.

A:

Q: Find the shaded region in the graph. y 2 +x soɔ = R/6 x/3 x/2 2/3 9/MG

A:

Q: Find the area of the shaded region. X = y 6 x = 27 / y2 6.

A: Area between the curve x=f(y) and x=g(y) on [a, b] is, A=∫abfy-gydy

Q: Find the area of the shaded region. y = x – 2 2+ y=V 1 2 3 4 | square units

A:

Q: Find the area of the shaded region below. y=Vx+ 2 x = 2 1 y = x+1 Area =

A: Form the definite integration of the difference of the given functions and simplify.

Q: Find the area of the shaded region. y 3y= 2 x+ 16 (1, 6) 6 4 (2, 4) (-2, 4) 2 y = 8- 2x -4 -2 2 4)

A:

Q: Find the area of the shaded region. y 15 y=7x-x² 10 (5, 10) y=2 x 4 8.

A:

Q: Find the area A of the shaded region where b = 4. y = |x| -b

A: Calculate the area of the shaded region where b=4.

Q: Find the area of the shaded region. x = y 20 x = 1000 / y? 20

A: To find: (a) The area of a shaded region. (b) Use the shown in the figure to find the following:…

Q: Find the area of the shaded region. y = x3 - 4x (3,15) C0,0) 3 33 O A.

A: The objective is to find the area of shaded region

Q: Find the total area of the shaded region below. 1 x+ y = 2 y = x2 1 2

A:

Q: 8. y = 3x² – 3, -2< xs 2

A:

Q: Find the total areas of the shaded regions

A: The shaded region is determined by two curves namely y=x2 on [0,1] and x+y=2⇒y=2-x on [1,2]. Also,…

Q: nd the total area of the shaded regions. Ay 25 y= X 25 = 20- 15 10 5- -8 -4 -2 (5- 9. -10- 寸

A: Given query is to find the total area of the shaded region.

Riemann Sum

Riemann Sums is a special type of approximation of the area under a curve by dividing it into multiple simple shapes like rectangles or trapezoids and is used in integrals when finite sums are involved. Figuring out the area of a curve is complex hence this method makes it simple. Usually, we take the help of different integration methods for this purpose. This is one of the major parts of integral calculus. 

Riemann Integral

Bernhard Riemann's integral was the first systematic description of the integral of a function on an interval in the branch of mathematics known as real analysis.