3) C = -40-25i -95-67i 53 +45i 204 + 82i 37 + 15i 88 + 45i -49 - 33i -180-50i -129-9i -317-61i 190 + 49i 616-32i 47 +21i 110 + 66i -63-45i -232-75i and λ=1+2i. A corresponding eigenvector would be:
3) C = -40-25i -95-67i 53 +45i 204 + 82i 37 + 15i 88 + 45i -49 - 33i -180-50i -129-9i -317-61i 190 + 49i 616-32i 47 +21i 110 + 66i -63-45i -232-75i and λ=1+2i. A corresponding eigenvector would be:
Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 66E: Show that A=[0110] has no real eigenvalues.
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