3) C = -40-25i -95-67i 53 +45i 204 + 82i 37 + 15i 88 + 45i -49 - 33i -180-50i -129-9i -317-61i 190 + 49i 616-32i 47 +21i 110 + 66i -63-45i -232-75i and λ=1+2i. A corresponding eigenvector would be:

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter7: Eigenvalues And Eigenvectors
Section7.1: Eigenvalues And Eigenvectors
Problem 66E: Show that A=[0110] has no real eigenvalues.
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3) C =
-40-25i
-95-67i
53 + 45i
204 + 82i
37 + 15i
-129-9i
-317-61i
88 + 45i
-49-33i
190 + 49i
-180 - 50i 616-32i
47+21i
110 + 66i
-63-45i
-232-75i
and λ = 1+2i. A corresponding eigenvector would be:
Transcribed Image Text:3) C = -40-25i -95-67i 53 + 45i 204 + 82i 37 + 15i -129-9i -317-61i 88 + 45i -49-33i 190 + 49i -180 - 50i 616-32i 47+21i 110 + 66i -63-45i -232-75i and λ = 1+2i. A corresponding eigenvector would be:
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