Question
Asked Sep 15, 2019
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Evaluate the definite integrals 

3 cos2 x sin T dx
(c)
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3 cos2 x sin T dx (c)

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Expert Answer

Step 1

We substitute cosx =t and sinxdx=-dt

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3 cos2 sin xdx = 3cos2 xsin xdx 0 cosx t sin xdx = dt x 0 tcos0 1 x Ttcos7 =-1 3 cos2 x sin xdx= 3| t2(-dt) 0

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Step 2

Then we use the result that integration...

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3 cos2 x sin xdx -3 tdt -3

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Math

Calculus