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3dx =1 2x8 In 국5-4 In2 In을-2 In-8 InLOnLOn

Question
3
dx =
1 2x
8 In 국
5
-4 In
2 In을
-2 In
-8 In
LOn
LOn
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3 dx = 1 2x 8 In 국 5 -4 In 2 In을 -2 In -8 In LOn LOn

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Step 1

Obtain the value of the integral as follows.

The given integral is,

3
4
-dx
1- 2х
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3 4 -dx 1- 2х

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Step 2

Let  u = 1-2x then du = -2dx.

Change the limit as follows.

If &...

3
4
1
-dx =-4 du
2u
1-2x
-3
47 1
2u
-3
-2[n
2[in
2[n3]-In|-5]
2[In (3)- In(5)]
=-2[n (5)-In (3)]
5
=-2 ln
3
In
b
3
4
dx is -2 ln
1- 2x
5
Thus, the value of the integral
3
Therefore, the appropriate option is four
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3 4 1 -dx =-4 du 2u 1-2x -3 47 1 2u -3 -2[n 2[in 2[n3]-In|-5] 2[In (3)- In(5)] =-2[n (5)-In (3)] 5 =-2 ln 3 In b 3 4 dx is -2 ln 1- 2x 5 Thus, the value of the integral 3 Therefore, the appropriate option is four

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Calculus

Integration

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