3 period phase shift| amplitude TT/6 T/3 T72 2/ 3 5TT / 6 T/2 -T/3 -T/6 71 /6 41/32a/2 5T /3 11T / 6 21 13T /6 7T / 3 5T/2 8T/3 17m TT R -1 -2 Manipulate the graph so that it matches f(x) = -3 cos(6z – 57). sive the coordinates of the points P, Q, R, S, and T (you may use 'pi' to represent 7 ): a. P = b. Q = C. R = d. S= e. T= 2.
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- If F admits continuous partial derivatives and the equation F ( 3x - y, z2 - x2)= 0 defines z implicitly as a function of x and y, then taking u = 3x - y and w = z2 - 2x then the value of the expression image1 corresponds to image 212 help use variation of parameters to finda general solution to the differntial equation given the function y1 and y2 are linearly independent solutions to the corresponding homogenous equation for t>0Obtain the Bezier curve of order 5 using Bernstein equation. Show the derivation
- sketch the graph of y = x^3 / (x^2 - 4), keep in mind the information provided:1. x and y intercept: (0, 0)2. Vertical asymptotes: x = 2, x = -23. There is no horizontal asymptote.4. Discontinuity at x = -2 and x = 2.5. First derivative: y’ = (x^4 - 12x^2) / (x^2 - 4)^26. Critical points: x = 0, x = 2√3, x = -2√37. Intervals of increase: (-∞, -2√3) U (2√3, ∞)8. Intervals of decrease: (-2√3, -2) U (-2, 0)9. Local maxima: (-3.46, -5.20) and (3.46, 5.20)10. Second derivative: y’’ = (8x^3 + 96x) / (x^2 - 4)^311. Critical numbers: (0, 0), (√12, 3√3), (-√12, -3√3)12. Point of inflection: (0, 0)13. Concave upward: (-2, 0) U (2, ∞)14. Concave downward: (-∞, -2) U (0, 2) A sketch of the graph (by hand) - Labeling of vertical asymptotes on the sketch - Labeling of horizontal asymptotes on the sketch - Labeling of x and y intercepts on the sketch - Labeling of maximum and minimum points on the sketch - Labeling of points of inflection on the sketch A sketch of the graph on Desmos with all key…24. Please help me find the rest 3 of the second partial derivatives to this calculus question.Differentiate y=excos(x2): y'= A. excos(x2)-2xsin(x2) B. -2xexsin(x2) C. ex(cos(x2)-2xsin(x2)) D. -exsin(x2)
- 1) draw points on the x axis 2) draw vertical lines at the veritcal asymptones 3) draw a horizontal line at the horizontal asymptote problem attached: A parametric cubic curve passes through the points (0,1), (2.5), (3,5) (5,-3) which are parameterized at t=0.1, 0.3, 0.6 and 0.9 , respectively. Determine the geometric coefficient matrix and the slope of the curve when t-0.5.1) Determine as 1st order partial derivatives of the functions below: