(3 - x) dx is equal to ° S (3 − x) dx + ["' (3 + x) dx °₁ (3 - x) dx ° L₁ (3+2)dz + f (3-2) x) dx x) dx °f*(3+z)dz x) dx

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A: Given :y'' − y' = et cos ty(0)=0, y'(0)=0

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A: NOTE: Refresh your page if you can't see any equations. . the auxiliary equation is given by

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A: Given problem:- Solve the given initial-value problem.   ydx/dy-x= 6y², x(8) = 1

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Q: 22:- Solve the following Equations by Gauss - Jordan method 2X+4Y-6Z=-4 X+ 5Y+3Z=10 X+3Y+2Z = 5

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A: We have to find the solution of given D. E.