3. Find the ranks and nullities of the following linear maps T: U → V, and find bases of the kernel and image of T in each case. (a) U = R³, V = R³, T|| B - (-)-(-)) = (b) U = R², V = R¹, T -0 basis of Ker(T) is (a) Rank(T)=2, Nullity (T)=1, a possible basis of Im(T) is (3) = = (b) Rank (T)=2, Nullity(T)=0, a possible basis of Im(T) is a () 0.0 (-). ( and the basis of Ker(T) is empty: 0. and a possible

Elementary Linear Algebra (MindTap Course List)
8th Edition
ISBN:9781305658004
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Linear Transformations
Section6.2: The Kernewl And Range Of A Linear Transformation
Problem 59E: Let T:R3R3 be the linear transformation that projects u onto v=(2,1,1). (a) Find the rank and...
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[EX3 Q3 Linear algebra] I have no problem with the rank and nullity, but I can't understand the solution provided for the basis of rank in both (a) and (b), could u please tell me why the provided solution can be the basis? thx :)

3. Find the ranks and nullities of the following linear maps T: U → V, and find
bases of the kernel and image of Tin each case.
a B
B-7
(a) U = R³, V = R³, T B
(0)
(b) U = R², V = R¹, T
(2)
basis of Ker(T) is
()
(b) Rank(T)=2, Nullity(T)=0
=
a possible basis of Im(T) is
(a) Rank(T)=2, Nullity(T)=1, a possible basis of Im(T) is
-0.0
a
a
a
(:¹).
and the basis of Ker(T) is empty: 0.
and a possible
Transcribed Image Text:3. Find the ranks and nullities of the following linear maps T: U → V, and find bases of the kernel and image of Tin each case. a B B-7 (a) U = R³, V = R³, T B (0) (b) U = R², V = R¹, T (2) basis of Ker(T) is () (b) Rank(T)=2, Nullity(T)=0 = a possible basis of Im(T) is (a) Rank(T)=2, Nullity(T)=1, a possible basis of Im(T) is -0.0 a a a (:¹). and the basis of Ker(T) is empty: 0. and a possible
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