3. Show, by direct differentiation, that for real number v (-1)* xv+2s J,(x) =E s!(s + v)! (2 s=0 satisfies the two recurrence relations 2v Jy-1(x) + Jy41(x) = -Ju(x) Jy-1(x) – Jy+1(x) = 2J', (x) %3D

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