+ 3. The following results were obtained from a disk diffusion test for a strain of Escherichia coli. Chemotherapeutic Zone of inhibition (mm) A B 7 10 C D 18 3 Which drug above (A, B, C, or D) is most effective against this E. coli strain? Which drug above (A, B, C, or D) is most effective against Staphylococcus aureus? Explain your answer.
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b. Which chemotherapeutic drug above (A, B, C, or D) is most effective against Staphylococcus aureus, if possible? Explain your answer.
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- Nitrate reduction test can be used to differentiate between Pseudomonads and Enterobacteriaceae. You inoculated your Nitrate broth with your unknown; after incubation, you added 5 drops of reagent A and 5 drops of reagent B. You observe a red color within 2 minutes. Is this a + or a - reaction? Assuming you did not get a red color, you then added a pinch of Zinc and this time tou obtained a red color. What does this mean?4) Consider the following list of hypothetical antibiotics, tested against Escherichia coli in a Kirby-Bauer test: Antibiotic Zone of Inhibition (mm) Astonostatin 12 Bodaciosporin 25 Crazifloxacin 5 Dorkimycin 16 When the above antibiotics were tested as treatments for E. coli infections in humans, it was found that Dorkimycin has virtually no effect on the infection, while Astonostatin is the most effective of the four antibiotics listed. Propose an explanation for this result. Based purely on these results, can you draw up a similar table for predicted zones f inhibition for Staphylococcus aureus? Why or why not?Antibiotic Code Zone of Inhibition (mm) S, I, or R? Penicillin P 15 Streptomycin S 8 Ampicillin A 25 Chloramphenicol C 14 Bacitracin B 5 QUESTIONS: Which antimicrobial agent was most effective against your organism? Can you determine from your results whether this antimicrobial agent will also be most effective against another bacterium? Why or why not? Is this technique measuring bacteriostatic effect, bactericidal effects, or both? Explain. 4) Consider the following list of hypothetical antibiotics, tested against Escherichia coli in a Kirby-Bauer test: Antibiotic Zone of Inhibition (mm) Astonostatin 12 Bodaciosporin 25 Crazifloxacin 5 Dorkimycin 16 When the above antibiotics were tested as treatments for E. coli infections in humans, it was found that Dorkimycin has virtually no effect on the infection, while Astonostatin is the most effective of the four antibiotics listed. Propose an explanation for this result. Based purely on these…
- If the volume of a Staphylococcus aureus cell is estimated at 0.5 μm3, how many cells could be accommodated, in principle, in 5 mL of saturated culture? (1 mL = 1 cm3). Show your calculations.If you have 4 compounds and you test them for antimicrobial activity using a disk diffusion assay and one is very active, one is moderately active, one is slightly active and one is not active at all, draw the disk, the zone of inhibition that you would see and a pretend numerical value to indicate the size of the zone in mm, give each one a number 1 – 4 and rank them from most effective to least effective as an antimicrobial.The table below shows the response of our ESKAPE safe relatives to 4 bacteria isolated from a master grid. We do not know the identity or any characteristics of the unknown bacteria. Each safe relative was spread onto a petri dish using aseptic technique. A grid pattern was taped to each plate and the unknown bacteria were patched into one of the squares. If there was no inhibition visible, including with a magnifying lens, the result was listed as -. If there was an inhibition zone between 1 and 10mm in diameter, the result is listed as +. If the inhibition zone was 10mm or greater, the result is listed as ++. In the lab, the MGC instructors plated all 6 of the ESKAPE pathogen safe relatives on LB agar plates. Then we patched Unknown Bacteria 5 from a Master plate onto the safe relative. The results are shown here: METRIC METRIC METRIC 1 B. subtilis S. epidermidis E. coli Complete the final column (Unknown Bacteria 5) of the table by selecting -, +, or ++ using the criteria in the…
- The table below shows the response of our ESKAPE safe relatives to 4 bacteria isolated from a master grid. We do not know the identity or any characteristics of the unknown bacteria. Each safe relative was spread onto a petri dish using aseptic technique. A grid pattern was taped to each plate and the unknown bacteria were patched into one of the squares. If there was no inhibition visible, including with a magnifying lens, the result was listed as -. If there was an inhibition zone between 1 and 10mm in diameter, the result is listed as +. If the inhibition zone was greater than 10mm, the result is listed as ++. Page 50 in your research guide states: "Some antibiotics are broad spectrum, meaning that they affect a wide range of bacteria. Other antibiotics have a narrow spectrum of activity. One anatomical feature that plays a significant role in the susceptibility of a microbe to a particular antibiotic is its cell wall composition (discussed in Section 8)". Research the cell wall…The table below shows the response of our ESKAPE safe relatives to 4 bacteria isolated from a master grid. We do not know the identity or any characteristics of the unknown bacteria. Each safe relative was spread onto a petri dish using aseptic technique. A grid pattern was taped to each plate and the unknown bacteria were patched into one of the squares. If there was no inhibition visible, including with a magnifying lens, the result was listed as -. If there was an inhibition zone between 1 and 10mm in diameter, the result is listed as +. If the inhibition zone was greater than 10mm, the result is listed as ++, Page 50 in your research guide states: "Some antibiotics are broad spectrum, meaning that they affect a wide range of bacteria. Other antibiotics have a narrow spectrum of activity. One anatomical feature that plays a significant role in the susceptibility of a microbe to a particular antibiotic is its cell wall composition (discussed in Section 8)". Research the cell wall…Results of Kirby Bauer test on E. Coli with penicilin , ampicilin, tetracycline, chloramphenicol disks showed zero zone of inhibition while there were zones around all these disks on S. aureus this should be interpreted as this drug is narrow spectrum a) True b) False
- Your colleague handed you a novel strain of coli that is purifying a protein with a 6xHisTag; they claim it is superior to the TOP10 cells you have been using. But even with a larger culture size, you discover that your protein yield—using the same Ni-NTA column—is quite low. You discover that the novel strain of Escherichia coli generates an unusually high quantity of dicarboxylic acids, a byproduct of the citric acid cycle that is recognized for its ability to function as an all-purpose metal chelator. What do you think the issue is with purifying IMAC protein with this new strain of E. coli?The production of a product P from a particular gram-negative bacteria follows the Monod growth law max Cs Co Ks + C, rg = with max (a) The reaction is to be carried out in a batch reactor with the initial cell concentration of Cco = 0.1 g/dm³ and substrate concentration of Cso = 20 g/dm³. = 1 h-¹, Ks = 0.25 g/dm³, and Y₁ = 0.5 g/g. c/s = p/c Cc Cco + Yc/s(Cs0 - Cs) = Plot rg, -rs-re, Cs, and Co as a function of time. The reaction is now to be car (b) dilution rate at which wash-out out in a CSTR with Cso = 20 g/dm³ and Cco = 0. What is the occurs? (c) For the conditions in part (b), what is the dilution rate that will give the maximum product rate 0.15 g/g? What are the concentrations Cc, C₁, Cp, and ―r, at this value of D? (g/h) if YImagine you have been given a liquid culture of yeast with a starting concentration of 3.67 x 10' cells/ml and are asked to carry out the sample dilution process shown in the figure below. 100μl 100μl 100μl 100μl 100μl 0.9ml 0.9ml 0.9ml H2O H₂O 6.9ml 0.9ml H₂O H₂O H₂O Original 10-1 102 10-3 104 Culture 105 100μl 100μl 100μl Plate A Plate B Plate C a. How many colonies should have been present on Plate A in this example? - Answers must be whole numbers as partial colonies are not expected. b. Imagine you carried out the same dilution scheme shown in the figure above, but now, you do not know the concentration of the original culture. If you counted 163 colonies on Plate B, what is the concentration of cells/ml in the original culture?