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3. The given equation is written in Point-Slope form. Convert the given equation into Slope Intercept form and Standard form. (8.F.2) 2 = y + 3 = 5 (x - 10) Slope Intercept form: 5. 5. 5. y+3 2 =—=—=— (x-10) 5 5y + 15 2(x-16) 5 Y 2x26 -15 -35 ड y=-7 Standard form: O

3. The given equation is written in Point-Slope form. Convert the given equation into Slope Intercept form and Standard form. (8.F.2) 2 = y + 3 = 5 (x - 10) Slope Intercept form: 5. 5. 5. y+3 2 =—=—=— (x-10) 5 5y + 15 2(x-16) 5 Y 2x26 -15 -35 ड y=-7 Standard form: O

College Algebra
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter1: Equations And Graphs
Section1.3: Lines
Problem 3E
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How do I get the correct answer?  Also how do I turn it into Standard form?

3. The given equation is written in Point-Slope form. Convert the given equation into Slope Intercept form and Standard form. (8.F.2) 1 y + 3 = = Slope Intercept form: 5. 5. 5. y ³4 +² 3 ² 2²/²/- (x - 10) 5 5y + 15 2(x-10) 5 2x26 -15 -35 5 2 5 (x - 10) y=-7 Standard form: 62% +: < 60.00
Transcribed Image Text:3. The given equation is written in Point-Slope form. Convert the given equation into Slope Intercept form and Standard form. (8.F.2) 1 y + 3 = = Slope Intercept form: 5. 5. 5. y ³4 +² 3 ² 2²/²/- (x - 10) 5 5y + 15 2(x-10) 5 2x26 -15 -35 5 2 5 (x - 10) y=-7 Standard form: 62% +: < 60.00
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