3. The perpendicular distance between two parallel tangents of a reverse curve is 35 m. The azimuth of the back tangent of the curve is 270°00' and the azimuth of the common tangent is 300°0O'. If the radius of the back curve is 150.00 meters and the stationing of P.R.C. is 10 + 140, find the station of the P.T. Use arc definition.

3. The perpendicular distance between two parallel tangents of a reverse curve is 35 m. The azimuth of the back tangent of the curve is 270°00' and the azimuth of the common tangent is 300°0O'. If the radius of the back curve is 150.00 meters and the stationing of P.R.C. is 10 + 140, find the station of the P.T. Use arc definition.

Traffic and Highway Engineering

5th Edition

ISBN:9781305156241

Author:Garber, Nicholas J.

Publisher:Garber, Nicholas J.

Chapter15: Geometric Design Of Highway Facilities

Section: Chapter Questions

Problem 7P

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Similar questions

The perpendicular distance between two parallel tangents of a reverse curve is 35m. The azimuth of the back tangent of the curve is 270°00’ and the azimuth of the common tangent is 300°00’. If the radius of the back curve is 150.00 meters and the stationing of P.R.C. is 10 + 140, find the station of the P.T. Use arc definition. Provide a complete solution with the necessary illustrations.
A horizontal curve with a deflection angle of 60o30' and degree of curvature of 5o as shown in Figure 5 is to be set out at whole station intervals of 100ft. If the point of curvature (PC) is located at a station 121+25.66, determine.i. the length of the curve and the station of PTii. the deflection angles VAp, VAq, VAv and Vas
Two tangents BC and CD intersect at an angle of 34° are to be connected with a simple curve. A point P on the curve is located 22.03m from point C and has a perpendicular distance of 2.89m from line BC. Calculate: a. The radius of the simple curveb. The length of chord connecting P.C. and point P.c. The stationing of P if vertex of the curve is at 10+100m
Two tangents BC and CD intersect at an angle of 34° are to be connected with a simple curve. A point P on the curve is located 22.03m from point C and has a perpendicular distance of 2.89m from line BC. Calculate: The radius of the simple curve The length of chord connecting P.C. and point P. The stationing of P if vertex of the curve is at 10+100m.
The bearings of backward and forward tangents are S 65°30’ E and N 75°40’ E, respectively. If the degree of curve is 8° for a full station of 20m and the stationing of the vertex is 5+005.25m, using arc basis determine the:a. Station of P.C. and P.T.b. Offset from tangent distance to the 4th station and its distance along the tangent from P.C.c. Offset from the Long chord to the 5th station and its distance along the Long chord from P.C.
The azimuths of the back and forward tangent of a spiral curve are 220° and 290° respectively. If the length of the spiral is 80m and the degree of the circular curve is 4°, determine: a. The distance between the vertex and the middle of the curve. b. The short tangent at the SC point. c. The long tangent at the SC point. d. The station of CS if the station of TS is at (7+028).
The centerline of two parallel tracks are connected by a reversed curve. The angle of intersection of the first curve is 15 degrees and the distance between parallel tracks is 30m. If the radius of the second curve is 300m. a. Compute the length of the long chord from P.C. to P.T. ANS. 229.839m b. Compute the radius of the first curve. ANS. 580.432m please also include the drawing of the curve
Two tangents AB and BC intersect at an angle of 24° are to be connected with a simple curve. A point P on the curve is located 21.03m from point B and has a perpendicular distance of 2.79m from line AB. Calculate the: The radius of the simple curve The length of chord connecting P.C. and point P. The stationing of P if vertex of the curve is at 10+120m.
two straight tangents of a two-line highway intersect at point B. The tangents have azmuths of 270 degree and 110 degree respectively. They are to be joined by a circular curve that has a radius of 7300ft. a) What are the tangent lengths? b) What is the length of curve? c) What is PI station if PC is Sta. 62+75'? d) What is the central angle for 500ft arc? e) If the curve is laid out by the tangent-offset method
3. A spiral curve 75 meters long connects a tangent with a 9 °30’ circular curve. If the stationing of TS is 11+020, determine: a. The spiral angle at the first quarter point b. The deflection angle at the end point c. The offset from the tangent at the second quarter point.
Two tangents of a simple curve have an azimuth of 250⁰15’ and 280⁰15’ respectively and intersect at V at station 10+314.62. It is required to shorten the curve to point C on the curve having a direction of N84⁰15’ W 50.42 m from the old PT without changing the degree of curve and the PC, determine the stationing of the new PT and the new vertex.
1. The tangents of a simple curve have bearings of N20°E and N80°E respectively. Theradius of the curve is 200m.a. Compute the external distance of the curve.b. Compute the middle ordinate of the curve.c. Compute the stationing of point A on the curve having a deflection angle of 6° fromthe P.C which is at 1 + 200.00