3. Use double integral to find the volume of the cylinder-like object that exists above the first quadrant on the xy plane and below the plane z = 10. The cross section of this "cylinder" on the xy plane is given by the polar equation r = 50 sin (20) (shown in figure, ignore the scale/numbers). Use the formula - V olume = zdA, R where R is the domain over which we are interested to find the volume under the surface z. Sketch the region R before doing the integration. (In polar coordinates, dA = rdrd0) Y 0.75 0.5 0.2 X -0,75 -0.5 0.25 0.5 0.75 -0.2 0.5 -0.75 Note that this "cylinder" is not the "usual circular" cylinder that we are familiar with

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter10: Analytic Geometry
Section10.6: The Three-dimensional Coordinate System
Problem 41E: Does the sphere x2+y2+z2=100 have symmetry with respect to the a x-axis? b xy-plane?
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3. Use double integral to find the volume of the cylinder-like object that exists
above the first quadrant on the xy plane and below the plane z = 10. The
cross section of this "cylinder" on the xy plane is given by the polar equation
r = 50 sin (20) (shown in figure, ignore the scale/numbers). Use the formula
-
V olume =
zdA,
R
where R is the domain over which we are interested to find the volume under
the surface z. Sketch the region R before doing the integration. (In
polar coordinates, dA = rdrd0)
Y
0.75
0.5
0.2
X
-0,75
-0.5
0.25
0.5
0.75
-0.2
0.5
-0.75
Note that this "cylinder" is not the "usual circular" cylinder that
we are familiar with
Transcribed Image Text:3. Use double integral to find the volume of the cylinder-like object that exists above the first quadrant on the xy plane and below the plane z = 10. The cross section of this "cylinder" on the xy plane is given by the polar equation r = 50 sin (20) (shown in figure, ignore the scale/numbers). Use the formula - V olume = zdA, R where R is the domain over which we are interested to find the volume under the surface z. Sketch the region R before doing the integration. (In polar coordinates, dA = rdrd0) Y 0.75 0.5 0.2 X -0,75 -0.5 0.25 0.5 0.75 -0.2 0.5 -0.75 Note that this "cylinder" is not the "usual circular" cylinder that we are familiar with
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