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- Below is how the arrays are represented ARRAY1[] = [1, 5, 6, 6, 9, 9, 9, 11, 11, 21] Here length of ARRAY1 is m. ARRAY2[] = [6, 6, 9, 11, 21, 21, 21] Here length of ARRAY2 is n. Array to be returned would be: ARRAY[] = [6, 9, 11, 21] ATTN : Further, please be reminded that you cannot use library functions to either sort and or perform the de-duplication operation. solve the problem in two ways In a separate implementation, code up a solution in such a way that your solution solves the problem with O(nlog(m)) time complexity 2 or O(mlog(n)) time complexity. Here log means to the base of 2. I’m sure you already know that the hint is to use Binary Search. In the form of sentences, as a comment in your code (at the bottom of your Solution2), you are required to suggest how can Solution2 be improved by leveraging the fact that both the arrays are already sorted. Suggest a solution so that your suggested solution can run linearly with O(m + n) time complexity. Your suggestion should be no…Q1: Suppose you are given an array A of n Your task is to sort n numbers stored in array A by reading the first element of A and placing it on its original position (position after sorting). Then read the second element of A, and place it on its original position. Continue in this manner for the first n-1 elements of A. What type of sorting is this? Write the algorithm and also mention the name of this sorting algorithm. What loop invariant does this algorithm maintain? Give the best-case and worst-case running times of this sorting algorithm.Trace each pass of selection, insertion, and quick sort for the list of values below. For quick sort, assumethat the pivot is the middle value in the portion of the array to be sorted. If there are an even number ofitems in the unsorted part of the list, so that two values “tie” for the middle value, pick the one on theleft as the pivot.The numbers are: 6, 3, 11, 4, 9, 8, 17 ,7
- LANGUAGE IS C++ Assignment 6B: Forwards and Backwards. Up to this point, we have sorted array values from smallest to largest. However, there are times when we need to do the reverse and sort from largest to smallest. We will implement a way to do this using Insertion Sort and Selection Sort.Take in an initial array size value from the user (C++ students: Check the Appendix for more information on how to do this) and a value for the highest possible value in the sequence. Fill the array with random values between 0 and that highest value. Then provide the user with the following options: Change the array’s elements with new random values◦ Use the numbers entered by the user initially for this; do not prompt the user for new numbers Sort from smallest to largest◦ Use Insertion Sort to sort the array so that the smallest value is at index 0, and the largest value is at the end of the array. Sort from largest to smallest◦ Use Selection Sort to sort the array so that the largest value…ALGO1(A)// A is an integer array, an index that starts at 11): for i=1 to n-1 do2): minIndex = findSmallest(A,i)3): exchange A[i] with A[minIndex] The sub-routine find the smallest(A, i) in Line 2, and returns the index of the smallest element in thesub-array A[i:n]Suppose the array below is provided as input to ALGO1 2 5 6 7 3 8 1 4 Fill in the Blanks At the end of the first iteration of the for loop (i.e. with i=1)1) a) the element at index 1 is : b) the element at index 4 is : c) the element at index 7 is :True or False For each statement below, indicate whether you think it is True or False. If you like, you can provide a description of your answer. 1) If you use binary search on a sorted array, the performance at worst is O(log n) 2) For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) 3) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value 4) Binary search can be used on an unsorted array
- True or False For each statement below, indicate whether you think it is True or False. If you use binary search on a sorted array, the performance at worst is O(log n) For the insert algorithm, if you use binary search to find the location to insert the new element, it will improve the overall performance of the algorithm to O(log n) For the update algorithm in a sorted array, all you have to do is use linear or binary search to find the element you want to change, and if you find it, you only need to change it to the new value Binary search can be used on an unsorted array Inserting elements into a sorted array is O(n) because you have to find the location to add the new element and then shift the remaining elements If the sorted array gets too large, the performance of binary search becomes O(n) For the delete algorithm, after you find the element to delete, you can make the algorithm run faster by replacing it with the last element in the array If you used binary search to…Please help me with this: using js create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your…Select true or false for the statements below. Explain your answers if you like to receive partial credit Select true or false for the statements below. Explain your answers if you like to receive partial credit Which of the following is true about searching elements in an unordered array? With the data is unsorted, search is O(n) because if the element you are looking for is not there, you have to check every element in the array If you start at the end of the array and traverse to index 0, search improves to O(log n) because you only have to look at half of the array If you get lucky with checking the first element and find it immediately, then the worst case performance of search improves to O(n^2) Which of the following is true about searching elements in an ordered array? You cannot use binary search on an ordered array so the performance is O(n) If there are no holes in the array and the elements are all next to each other, then the performance for search improves to…
- Write the state of the elements of each of the following arrays after each pass of the outermost loop of the selection sort algorithm has occurred (after each element is selected and moved into place).int[] numbers1 = {63, 9, 45, 72, 27, 18, 54, 36};int[] numbers2 = {37, 29, 19, 48, 23, 55, 74, 12};Below is your exercise for Basic Sorts. For submitting your answers, you can either send me an updated Word document with your answers, email your answers directly, or even take a screen shot of your work on paper if you like. In all cases, email me your answers when you feel ready. Use the following array of numbers for each of the sorting tasks below: 6 2 8 1 7 5 3 4 Bubble Sort (not optimized) – show what the array looks like each time the swap operation is performedusing the bubble sort algorithm (not optimized, meaning no use of swapFlag) Selection Sort - show what the array looks like each time the swap operation is performed using the selection sort algorithm Insertion Sort – show what the array looks like at the end of each outer loop iteration of the insertion sort algorithmJAVAUse array {"shall", "not", "perish", "from", "the", "earth"} to simulate selection sort. For each iteration, write down the value of initial value and index, the minimum value and its index, and then write down the array after each iteration.