3. You currently drive 240 miles per week in a car that gets 16 miles per gallon. A new car cost $13,000 (after trade-in) and gets 40 miles per gallon. Insurance and repairs for the old car are $600 per year and $1400 per year, respectively. The insurance for the new car is $800 per year and there are no repair costs for the first 5 years. Assume gas costs $3.50 per gallon for the next 5 years. (a) What is the cost of keeping your old car for the next 5 years? (b) What is the cost of the new car for the next 5 years? (c) How much money might you save by choosing the less expensive option?

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 26EQ
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Currently drive 240 miles per week in a car they get 16 miles per gallon. A new car cost $13,000…. (See photo)
3. You currently drive 240 miles per week in a car that gets 16 miles per gallon. A new car cost $13,000
(after trade-in) and gets 40 miles per gallon. Insurance and repairs for the old car are $600 per year
and $1400 per year, respectively. The insurance for the new car is $800 per year and there are no
repair costs for the first 5 years. Assume gas costs $3.50 per gallon for the next 5 years.
(a) What is the cost of keeping your old car for the next 5 years?
(b) What is the cost of the new car for the next 5 years?
(c) How much money might you save by choosing the less expensive option?
Transcribed Image Text:3. You currently drive 240 miles per week in a car that gets 16 miles per gallon. A new car cost $13,000 (after trade-in) and gets 40 miles per gallon. Insurance and repairs for the old car are $600 per year and $1400 per year, respectively. The insurance for the new car is $800 per year and there are no repair costs for the first 5 years. Assume gas costs $3.50 per gallon for the next 5 years. (a) What is the cost of keeping your old car for the next 5 years? (b) What is the cost of the new car for the next 5 years? (c) How much money might you save by choosing the less expensive option?
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