Homework Help is Here – Start Your Trial Now!
Engineering
Chemical Engineering
3.5 Two bulbs are connected by a tube, 0.002 m in diameter and 0.20 m in length. Initially bulb 1 contains argon, and bulb 2 con- tains xenon. The pressure and temperature are maintained at 1 atm and 105°C, at which the diffusivity is 0.180 cm²/s. At time t = 0, diffusion is allowed to occur between the two bulbs. At a later time, the argon mole fraction in the gas at end 1 of the tube is 0.75, and 0.20 at the other end. Determine at the later time: (a) The rates and directions of mass transfer of argon and xenon (b) The transport velocity of each species (c) The molar average velocity of the mixture

3.5 Two bulbs are connected by a tube, 0.002 m in diameter and 0.20 m in length. Initially bulb 1 contains argon, and bulb 2 con- tains xenon. The pressure and temperature are maintained at 1 atm and 105°C, at which the diffusivity is 0.180 cm²/s. At time t = 0, diffusion is allowed to occur between the two bulbs. At a later time, the argon mole fraction in the gas at end 1 of the tube is 0.75, and 0.20 at the other end. Determine at the later time: (a) The rates and directions of mass transfer of argon and xenon (b) The transport velocity of each species (c) The molar average velocity of the mixture

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
See similar textbooks
icon
Related questions
Question
100%

can someone plz help me re-do this

 

please type of solution 

I am trying to do A, B, C this is what i got 

To determine the rates and directions of mass transfer of argon and xenon, we can use Fick's law of diffusion.

Using Fick's law for argon (A)

Where, JA is is the molar flux of Argon (mass transfer rate per unit area)

C is total concentration 

∆z is difference in position along the length of the tube.

xA1 is the mole fraction of argon in bulb 1 at later time 

xA2 is the mole fraction of argon in bulb 2 at later time

 

 

3.5 Two bulbs are connected by a tube, 0.002 m in diameter and 0.20 m in length. Initially bulb 1 contains argon, and bulb 2 con- tains xenon. The pressure and temperature are maintained at 1 atm and 105°C, at which the diffusivity is 0.180 cm²/s. At time t = 0, diffusion is allowed to occur between the two bulbs. At a later time, the argon mole fraction in the gas at end 1 of the tube is 0.75, and 0.20 at the other end. Determine at the later time: (a) The rates and directions of mass transfer of argon and xenon (b) The transport velocity of each species (c) The molar average velocity of the mixture
Transcribed Image Text:3.5 Two bulbs are connected by a tube, 0.002 m in diameter and 0.20 m in length. Initially bulb 1 contains argon, and bulb 2 con- tains xenon. The pressure and temperature are maintained at 1 atm and 105°C, at which the diffusivity is 0.180 cm²/s. At time t = 0, diffusion is allowed to occur between the two bulbs. At a later time, the argon mole fraction in the gas at end 1 of the tube is 0.75, and 0.20 at the other end. Determine at the later time: (a) The rates and directions of mass transfer of argon and xenon (b) The transport velocity of each species (c) The molar average velocity of the mixture
B) A) Vargon C VAmass = (VA-mass) difussion na A * C * = Vargon Argon JAwill be constant throughout length 2.2 * 10-8 3.2 10-4 (0.180) 0.0314 Vargon = Vxenon Argon -10 Argon = 0.66 @ 10cm, 2.212 * 10-³ = = 0.34 -2.2 * 0.0314(3) (2 10-4) Argon 2.212 * 10-³ 10-3 Xxenon * 2.2 * 10-³ = P 1 Rt 82.6(378) C) Molar average velocity is Xxenon * Vxenon +Xargon Vargon -(Argon - 0.75) so 0.34 = = 3.31 * 10-3 = = 3.2 * cm S 10-³ cm S -6.64* 10-4 mol cm³ - & JA = CDAB ΔΖ (0.34)(-6.64 10-³) + 0.66(3.31 * 10-³) = 0
Transcribed Image Text:B) A) Vargon C VAmass = (VA-mass) difussion na A * C * = Vargon Argon JAwill be constant throughout length 2.2 * 10-8 3.2 10-4 (0.180) 0.0314 Vargon = Vxenon Argon -10 Argon = 0.66 @ 10cm, 2.212 * 10-³ = = 0.34 -2.2 * 0.0314(3) (2 10-4) Argon 2.212 * 10-³ 10-3 Xxenon * 2.2 * 10-³ = P 1 Rt 82.6(378) C) Molar average velocity is Xxenon * Vxenon +Xargon Vargon -(Argon - 0.75) so 0.34 = = 3.31 * 10-3 = = 3.2 * cm S 10-³ cm S -6.64* 10-4 mol cm³ - & JA = CDAB ΔΖ (0.34)(-6.64 10-³) + 0.66(3.31 * 10-³) = 0
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Introduction to Chemical Engineering Thermodynami…
Introduction to Chemical Engineering Thermodynami…
Chemical Engineering
ISBN:
9781259696527
Author:
J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:
McGraw-Hill Education
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemical Engineering
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
Elements of Chemical Reaction Engineering (5th Ed…
Elements of Chemical Reaction Engineering (5th Ed…
Chemical Engineering
ISBN:
9780133887518
Author:
H. Scott Fogler
Publisher:
Prentice Hall
Process Dynamics and Control, 4e
Process Dynamics and Control, 4e
Chemical Engineering
ISBN:
9781119285915
Author:
Seborg
Publisher:
WILEY
Industrial Plastics: Theory and Applications
Industrial Plastics: Theory and Applications
Chemical Engineering
ISBN:
9781285061238
Author:
Lokensgard, Erik
Publisher:
Delmar Cengage Learning
Unit Operations of Chemical Engineering
Unit Operations of Chemical Engineering
Chemical Engineering
ISBN:
9780072848236
Author:
Warren McCabe, Julian C. Smith, Peter Harriott
Publisher:
McGraw-Hill Companies, The
SEE MORE TEXTBOOKS