3.54 Figure 3.23 shows a closed tank that contains gasoline float- ing on water. Calculate the air pressure above the gasoline. Air Gasoline 0.50 m (sg = 0.68) Water 1.00 m 457 mm 381 mm GM odiesa 8. Mercury (sg = 13.54)
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- A tank contains ail sp. gr. 0.80, gasoline sp. gr. 0.90 and seawater sp. gr. 1.03. If the depths of the liquids are 0.5 m, 0.8 m and 1 m for oil, gasoline and seawater respectively. Find the pressure at a depth of 1.2 m. a. 28.124 Kpa b. 21.092 Kpa c. 16.04 Kpa d. 10.104 Kpa The answer for this is letter D which is 10.104 Kpa however I dont know the exact solution.The system in Figure 2-5 is at 20oC. If atmospheric pressure is 101.03 kPa and the absolute pressure at the bottom of the tank is 231.3 kPa, what is the specific gravity of olive oil? Note: density of water=9.79 kN/m3 (specific gravity SAE oil is 0.89, h SAE oil is 1.5m, h water is 2.5m, H olive oil is 2.9m, h mercury is 0.4m, specific gravity mercury is 13.6 ) and use g=9.79m/s2. a) 1.39 b) 1.29 c) 1.49 d) 1.59 e) none of the abovethe reading of an automobile fuel gage is proportional to the gage pressure at the bottom of the tank. if the tank is 30 cm. deep, and is contaminated with 3.42 cm. of water at the bottom, how many meters of air remains at the top when the gage indicates "FULL"? use weight of: gasoline = 6.62 kN/m^3; air = 14.67 N/m^3. the tank is closed.
- The reading of an automobile fuel gage is proportional to the gage pressure at the bottom of the tank. If the tank is 30 cm. deep, and is contaminated with 3.05 cm. of water at the bottom, how many meters of air remains at the top when the gage indicates "FULL"? Use Unit weight of: gasoline = 6.24 kN/m3; air = 12.6 N/m3. The tank is closed. ANSWER : 0.017A venturi meter with throat diameter of 37.5 mm and coefficient of discharge of 0.957 is connected to a 75 mm pipe to measure the discharge of oil with specific gravity of 0.853. A differential gage filled with liquid with specific gravity of 1.35 is connected. If there is a 415 mm difference in the height of the fluid in the meter, what is the flowrate of oil? (PLEASE USE BERNOULLI'S ENERGY EQUATION) INCLUDE COMPLETE SOLUTION PLEASEThe pipe is 25mm with friction factor of 0.022. The second tank is vented. H1=1.4m H2=4.5m H3=1.0m X1=14.9m X2=2.7m Calculate the pressure(kPa) above the gasoline in the first tank that will result in a flowrate of 400 liters/min.
- Calculate the diameter of the nozzle (in mm) by a jet of water discharging freely out of a nozzle, fitted to a pipe 300 m long and 100 mm diameter with coefficient of friction as 0.01. The available head at the nozzle is 90 m. a. 33 b. 25.4 c. 372 d. 10.29A liquid of specific gravity of 1.75 flows in a 6 cm horizontal pipe. The total energy at certain point in the flow is 80 J/N (joules/newton). The elevation of the pipe above the fixed datum is 2.6 m. If the pressure is 75 kPa. Determine the velocity of flow in m/s. A.23.86 b.32.45 c.37.85 d.42.25lWater in pressurized cylindrical tank 40 ft. in diameter discharges into the atmospherethrough a nozzle 4 inches in diameter. Neglecting friction, and assuming unsteady flow;find the time required for the water in the tank to drop from a level of 50 ft. above thenozzle to 2 ft. above it if the tank is under constant gauge pressure of 1 atm. State anyassumptions.