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- Draw a simple graph G with 7 vertices and δ(G) ≥ 3 that has no Euleriancycle, but has an Eulerian trail. Describe how you obtained this graph and whether the solution isunique (up to isomorphism). Justify your answer.1. show that every simple finite graph has two vertices of the same degree. 2.prove that the degree of a regular complete tripartite graph kr,s,t with n vertices is given by 2n/3. 3. Draw a picture of the graph weather if it is a simple or not G1=(V1,E1)V1=a,b,c,e}E1={ab,bc,ac,ad,de}The symmetric difference graph of two graphs G1 = (V, E1) and G2 = (V, E2) on the samevertex set is defined as G1△G2 := (V, E1△E2). Remember that E1△E2 := (E1 \ E2) ∪(E2 \ E1). If G1 and G2 are eulerian, show that every vertex in G1△G2 has even degree
- Euler graph of order 51. example of a simple graph with 2 vertices 2. example of a simple disconnected graph with 3 vertices 3. example of a graph that is not simple 4. example of a cycle with 3 vertices 5. example of a complete graph with 4 verticesLet Vn be the set of connected graphs having n edges, vertex set [n], and exactly one cycle. Form a graph Gn whose vertex set is Vn. Include {gn, hn} as an edge of Gn if and only if gn and hn differ by two edges, i.e. you can obtain one from the other by moving a single edge. Tell us anything you can about the graph Gn. For example, (a) How many vertices does it have? (b) Is it regular (i.e. all vertices the same degree)? (c) Is it connected? (d) What is its diameter?
- Show that the first graph below can be constructed for the second graph. 2. Verify the Euler’s formula in the first graph.(i) Let e1, e2, . . . , one connection of the graph G and let xi−1 and xi be the sites of the connection ei (1 ≤ i ≤ n). Show that every closed walk (e1, e2, . . . , en) is of length at least 3 with pairs of distinct pointsx1, x2, . . . , xn cycles.(ii) A graph containing no cycles is called acyclic. A walk is acyclic if the subgraph consisting of points and links of the walk is acyclic. Prove: a walk has all distinct points if and only if it is an acyclic sequence.(iii) If and are in different points of the graph G and if there is a walk in G from u to v, show that then there is an acyclic sequence from u to v.(Explain precisely that every shortest walk from u to v is actually an acyclic path.)I know that there is an answered question on the question bank, but there are syntax errors the computer caused, so I don't understand it correctly. Prove that the two graphs below are isomorphic. Figure 4: Two undirected graphs. Each graph has 6 vertices. The vertices in the first graph are arranged in two rows and 3 columns. From left to right, the vertices in the top row are 1, 2, and 3. From left to right, the vertices in the bottom row are 6, 5, and 4. Undirected edges, line segments, are between the following vertices: 1 and 2; 2 and 3; 1 and 5; 2 and 5; 5 and 3; 2 and 4; 3 and 6; 6 and 5; and 5 and 4. The vertices in the second graph are a through f. Vertices d, a, and c, are vertically inline. Vertices e, f, and b, are horizontally to the right of vertices d, a, and c, respectively. Undirected edges, line segments, are between the following vertices: a and d; a and c; a and e; a and b; d and b; a and f; e and f; c and f; and b and f.
- 3. (b) The degree of every vertex of a graph G is one of three consecutive integers. If, for each of the three consecutive integers x, the graph G contains exactly x vertices of degree x, prove that two-thirds of the vertices of G have odd degree. (c) Construct a simple graph with 12 vertices satisfying the property described in part (b).can u solve 5.2 in the exercise . here s the solution of 5.1: Step 1: Understanding the Path Edge Cover Problem In the Path Edge Cover problem, we are given a directed acyclic graph A with two distinguished nodes s (source) and t (sink). The objective is to find the minimum number of directed s-t paths that cover all edges in A. In other words, each edge in the graph must be included in at least one of the chosen paths. arrow_forward Step 2: Transforming Graph A into Graph G To transform A into a graph G suitable for the minimum flow problem, we perform the following steps: Node Splitting: For each node v in A (except s and t), we split v into two nodes vin and vout. Then we add an edge from vin to vout with a lower capacity of 1 and an upper capacity of 1. This enforces that any flow passing through v must be part of exactly one path. Edge Transformation: For each edge (u,v) in A, we create an edge (uout,vin) in G with a lower capacity of 0 and an upper capacity…How can I prove the following: Let G be a 2-connected graph. If e and f are parallel edges in G, then G\e is 2-connected. (Without deleting edges or vertices. However edge contraction is allowed)