3+1 f(r) = 4r² – 1 g(x) = h(1) = VI 2т + 1 13. (f - 9)(г) Sz3 + 4x? – 3r – 4 (A) 2т +1 8r3 + 4r? – 1 +3 (C) 2т + 1 8r3 + 4x2 — т+2 (В) 2т + 1 (D) 8r3 + 4r2 -r+3 2т + 1 14. f(т) g(x) (A) 2г? + 51 — 3 (c) 2г? + 4г - 3 (D) 2r? – 4r +3 (В) 2л? — 5х —3 15. (fo f)(г) (А) 16х4 — - 8z2 (С) 64г* — 32г?+3 (В) 64т4 — 3212 + 4 (D) 1
3+1 f(r) = 4r² – 1 g(x) = h(1) = VI 2т + 1 13. (f - 9)(г) Sz3 + 4x? – 3r – 4 (A) 2т +1 8r3 + 4r? – 1 +3 (C) 2т + 1 8r3 + 4x2 — т+2 (В) 2т + 1 (D) 8r3 + 4r2 -r+3 2т + 1 14. f(т) g(x) (A) 2г? + 51 — 3 (c) 2г? + 4г - 3 (D) 2r? – 4r +3 (В) 2л? — 5х —3 15. (fo f)(г) (А) 16х4 — - 8z2 (С) 64г* — 32г?+3 (В) 64т4 — 3212 + 4 (D) 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter9: Systems Of Linear Equations
Section9.2: The Substitution Method
Problem 12WE
Related questions
Question
s 13 14 15
Transcribed Image Text:3+1
f(r) = 4r² – 1
g(x) =
h(r) = VI
2т + 1
13. (f - 9)(г)
Sz3 + 4x? – 3r – 4
(A)
2т +1
8r3 + 4r? – 1 +3
(C)
2т + 1
8r3 + 4x2 — т+2
(В)
2т + 1
(D)
8r3 + 4r2 -r+3
2т + 1
14. f(т) g(x)
(A) 2г? + 51 — 3
(c) 2г? + 4г - 3
(D) 2r? – 4r +3
(В) 2л? — 5х —3
15. (fo f)(г)
(А) 16х4 —
- 8z2
(С) 64г* — 32г?+3
(В) 64т4 — 3212 + 4
(D) 1
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 3 images
Recommended textbooks for you
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell