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-32 ft/sec?. Assume that the in n object's downward acceleration is given by y"(t) = elocity is y' (0) = -100ft/s and the initial position is y(0) = 100, 000 ft. %3D %3D 1. Evaluate y"(t) dt. A. -32 + C C. -32t + C B. -32t D. -32 2. We let V (t) the velocity function. What is V(t)? A. V(t) = B. V(t) = -32 3. What is the value of C in the velocity function? C.V (t) = -32t + C D. V(t) = -32t %3D = -32 + C C. 100 A. - 100 D. 32 -32

-32 ft/sec?. Assume that the in n object's downward acceleration is given by y"(t) = elocity is y' (0) = -100ft/s and the initial position is y(0) = 100, 000 ft. %3D %3D 1. Evaluate y"(t) dt. A. -32 + C C. -32t + C B. -32t D. -32 2. We let V (t) the velocity function. What is V(t)? A. V(t) = B. V(t) = -32 3. What is the value of C in the velocity function? C.V (t) = -32t + C D. V(t) = -32t %3D = -32 + C C. 100 A. - 100 D. 32 -32

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Use the word problem below to answer questions 1-7. An object's downward acceleration is given by y"(t) = -32 ft/sec2. Assume that the initial velocity is y'(0) = -100ft/s and the initial position is y(0) = 100, 000 ft. 1. Evaluate f y"(t) dt. A. -32 + C C. -32t + C B. -32t D. -32 2. We let V(t) the velocity function. What is V(t)? A. V(t) = -32 + C B. V(t) = -32 3. What is the value of C in the velocity function? C. V (t) = -32t + C D. V (t) = -32t C. 100 A. - 100 D. 32 В. -32 4. What is f y'(t)dt? A. - 16t2 -100 t +C B. - 16t2 -100 t C. – 16t2 + 100 t +C D.- 16t2 + 100 t-C 5. We let y(t) be the position function. What is the position function? A. p(t) = – 16t2 – 100 t + C B. p(t) = - 16t2 – 100 t 6. What is the value of C in the position function? A. - 100 C. p(t) = - 16t2 + 100 t + C D. p(t) = - 16t2 + 100 t – C C. 100 D. 100, 000 B. - 100, 000 7. What is the final position function (with the value of C substituted)? A. (t) = - 16t? – 100 t - 100 B. p(t) = - 16t2 – 100 t – 100,000 8-10. A car is travelling along a straight, level road at 45 miles per hour (66 feet per second) when the driver is forced to apply the brakes to avoid an accident. The brakes supply a constant deceleration of 22ft/sec? (feet per second, per second), how far does the car travel before coming to a complete stop? A. 99ft В. 297 ft C. p(t) = - 16t2 + 100 t + 100 D. p(t) = - 16t? + 100 t + 100,000 C. 99 mi. D. 36 ft.
Transcribed Image Text:Use the word problem below to answer questions 1-7. An object's downward acceleration is given by y"(t) = -32 ft/sec2. Assume that the initial velocity is y'(0) = -100ft/s and the initial position is y(0) = 100, 000 ft. 1. Evaluate f y"(t) dt. A. -32 + C C. -32t + C B. -32t D. -32 2. We let V(t) the velocity function. What is V(t)? A. V(t) = -32 + C B. V(t) = -32 3. What is the value of C in the velocity function? C. V (t) = -32t + C D. V (t) = -32t C. 100 A. - 100 D. 32 В. -32 4. What is f y'(t)dt? A. - 16t2 -100 t +C B. - 16t2 -100 t C. – 16t2 + 100 t +C D.- 16t2 + 100 t-C 5. We let y(t) be the position function. What is the position function? A. p(t) = – 16t2 – 100 t + C B. p(t) = - 16t2 – 100 t 6. What is the value of C in the position function? A. - 100 C. p(t) = - 16t2 + 100 t + C D. p(t) = - 16t2 + 100 t – C C. 100 D. 100, 000 B. - 100, 000 7. What is the final position function (with the value of C substituted)? A. (t) = - 16t? – 100 t - 100 B. p(t) = - 16t2 – 100 t – 100,000 8-10. A car is travelling along a straight, level road at 45 miles per hour (66 feet per second) when the driver is forced to apply the brakes to avoid an accident. The brakes supply a constant deceleration of 22ft/sec? (feet per second, per second), how far does the car travel before coming to a complete stop? A. 99ft В. 297 ft C. p(t) = - 16t2 + 100 t + 100 D. p(t) = - 16t? + 100 t + 100,000 C. 99 mi. D. 36 ft.
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