35 •• An imaginary right circular cone (Figure 22-40) that has a base angle and a base radius R is in charge free region that has a uniform electric field E (field lines are vertical and parallel to the cone's axis). What is the ratio of the number of field lines per unit area penetrating the base to the number of field lines per unit area penetrating the conical surface of the cone? Use Gauss's law in your answer. (The field lines in the figure are only a representa- tive sample.) 36 In the atmosphere and at an altitude of 250 m, you measure the electric field to be 150 N/C directed down- ward, and you measure the electric field to be 170 N/C directed downward at an alti- tude of 400 m. Calculate the volume charge density of the atmosphere in the region between altitudes of 250 m and 400 m, assuming it to be uniform. (You may neglet the curvature of Earth. Why?) E 0
35 •• An imaginary right circular cone (Figure 22-40) that has a base angle and a base radius R is in charge free region that has a uniform electric field E (field lines are vertical and parallel to the cone's axis). What is the ratio of the number of field lines per unit area penetrating the base to the number of field lines per unit area penetrating the conical surface of the cone? Use Gauss's law in your answer. (The field lines in the figure are only a representa- tive sample.) 36 In the atmosphere and at an altitude of 250 m, you measure the electric field to be 150 N/C directed down- ward, and you measure the electric field to be 170 N/C directed downward at an alti- tude of 400 m. Calculate the volume charge density of the atmosphere in the region between altitudes of 250 m and 400 m, assuming it to be uniform. (You may neglet the curvature of Earth. Why?) E 0
Related questions
Question
just number 35 please
![35
An imaginary right circular cone (Figure 22-40) that has a
base angle and a base radius R is in charge free region that has
a uniform electric field Ē (field lines are vertical and parallel to the
cone's axis). What is the ratio of the number of field lines per unit
area penetrating the base to the number of field lines per unit area
penetrating the conical surface of the cone? Use Gauss's law in your
answer. (The field lines in the
figure are only a representa-
tive sample.)
36
In the atmosphere
and at an altitude of 250 m,
you measure the electric field
to be 150 N/C directed down-
ward, and you measure the
electric field to be 170 N/C
directed downward at an alti-
tude of 400 m. Calculate the
volume charge density of
the atmosphere in the region
between altitudes of 250 m
and 400 m, assuming it to be
uniform. (You may neglet the
curvature of Earth. Why?)
R
E
8](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe9a96325-e1c3-4b19-b1b4-8ad61c01db3d%2F2967ef55-01ab-48ed-9675-388b3f01634d%2Fnzl97io_processed.png&w=3840&q=75)
Transcribed Image Text:35
An imaginary right circular cone (Figure 22-40) that has a
base angle and a base radius R is in charge free region that has
a uniform electric field Ē (field lines are vertical and parallel to the
cone's axis). What is the ratio of the number of field lines per unit
area penetrating the base to the number of field lines per unit area
penetrating the conical surface of the cone? Use Gauss's law in your
answer. (The field lines in the
figure are only a representa-
tive sample.)
36
In the atmosphere
and at an altitude of 250 m,
you measure the electric field
to be 150 N/C directed down-
ward, and you measure the
electric field to be 170 N/C
directed downward at an alti-
tude of 400 m. Calculate the
volume charge density of
the atmosphere in the region
between altitudes of 250 m
and 400 m, assuming it to be
uniform. (You may neglet the
curvature of Earth. Why?)
R
E
8
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 4 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)