350 mm fe = 21 MPa fy = 414 MPa Ø = 0.75 Stirrups – 10mm Ø 600 mm
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- Tube diameter 145 mm(xx=45)A line was recorded as 1750.00 meters long. The standard tape weighs0.65 kg , 30.00m long at 20°C under a 50N pull. During the actualobservation the temperature was 5°C and the tape was suspended undera 75N pull. It was also found that the tape is 3.00mm too long. If the linewas inclined at 3%. E = 200GPa, A = 2.50mm² and the coefficient of linearexpansion is 0.0000116 m/°C.(a) What is the actual inclined distance?(b) What is the actual horizontal distance.What must be the pull in a (7)(10) meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10% m? E = 2x101 N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends. Fundamentals of surveying
- Convert 59 cm/sec to in/min 1 in= 2.54 cm 1 min= 60 secWhat must be the pull in a 70 meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10^-6m? E = 2x10^11N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends.a.) Q=0.56m/s. V=1.16m/s b.)D=420mm. q=5.5x10^-3m^3/s That is the answer need some solutions
- A 100 m tape weighing 3 kg was standardized and found to be 0.02 m short at temperature of 10degC and a 30 N pull when supported throughout. The 1324.55 – meter distance measured is an inclined distance whose difference in elevation between the points is 2 m. What is the correct distance? a. 1 324.28 m b. 1 234.18m c. 1 345.83 m d. 1 432.11 mA 50 m steel tape is used to measure a rectangle at 20°C with a pull of 55 N. The sides are recorded as 155.90 m and 121.00 m. The average temperature during measurement is 30°C with a pull of 55 N. C = 0.0000116/°C. Compute the total corection for the width.An engineer used a 30 m tape in measuring an inclined ground 459.20 m long. The difference between the starting point and end point is 1.20 m. The tape is of standard length at a temperature of 100 C and a pull of 50 N. During measurement the temperature reading was 15 0 C and a pull of 75N applied at both ends. A= 6.5mm2 ; E = 200GPa; K = 0.0000116 m/C0 . The mass of the tape is 0.075kg/m. Determine the horizontal distance.
- Compute for m if fc'=32MPa and fy=400MPa. Use 3 decimal placesWhat must be the pull in a 70 meters tape in order to eliminate the sag and temperature correction, given the following? a = 7x10% m? E = 2x101 N/m? Weight of tape, 11 N Po = 10kg To = 22°C T = 20°C K= 0.0000116/°C The tape length is supported at both ends.A wooden block (40 cm wide (b), 20 cm long (h) and 15 cm deep) floats on the seawater (specific gravity, sg = 1.025) with a depth of immersion is 12 cm. Calculate the position of metacentre, MG and justify the stability of block with the aid of sketch.