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36. Given the following thermochemical equations 2H,(g) + O,(g) - 2H,O(1) AH = -571.6 kJ N,O5(g) + H,O(1) → 2HNO;(1) AH = -73.7 kJ N2(g) +0,(g) + H;(g) – HNO,(1) AH = - 174.1 kJ calculate AH for the formation of one mole of dinitrogen pentoxide from its elements in their stable state at 25°C and 1 atm.

36. Given the following thermochemical equations 2H,(g) + O,(g) - 2H,O(1) AH = -571.6 kJ N,O5(g) + H,O(1) → 2HNO;(1) AH = -73.7 kJ N2(g) +0,(g) + H;(g) – HNO,(1) AH = - 174.1 kJ calculate AH for the formation of one mole of dinitrogen pentoxide from its elements in their stable state at 25°C and 1 atm.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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36. Given the following thermochemical equations 2H,(g) + O,(g) – 2H,O(1) AH = -571.6 kJ ΔΗ N,O5(g) + H,O(1) 2HNO3(1) AH = -73.7 kJ N;(g) +0,(g) + H;(g) → HNO,(1) AH = - 174.1 kJ calculate AH for the formation of one mole of dinitrogen pentoxide from its elements in their stable state at 25°C and 1 atm.
Transcribed Image Text:36. Given the following thermochemical equations 2H,(g) + O,(g) – 2H,O(1) AH = -571.6 kJ ΔΗ N,O5(g) + H,O(1) 2HNO3(1) AH = -73.7 kJ N;(g) +0,(g) + H;(g) → HNO,(1) AH = - 174.1 kJ calculate AH for the formation of one mole of dinitrogen pentoxide from its elements in their stable state at 25°C and 1 atm.
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