MATLAB (already have the answer) UPVOTE WILL BE GIVEN. PLEASE SEE THE ATTACHED PHOTO FOR THE QUESTION AND SOLUTION. WHAT YOU WILL DO IS TO INPUT THE SCRIPT IN MATLAB. PLEASE TAKE A SCREENSHOT OF THE SCRIPT AND COMMAND WINDOW.
MATLAB (already have the answer) UPVOTE WILL BE GIVEN. PLEASE SEE THE ATTACHED PHOTO FOR THE QUESTION AND SOLUTION. WHAT YOU WILL DO IS TO INPUT THE SCRIPT IN MATLAB. PLEASE TAKE A SCREENSHOT OF THE SCRIPT AND COMMAND WINDOW.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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MATLAB (already have the answer)
UPVOTE WILL BE GIVEN. PLEASE SEE THE ATTACHED PHOTO FOR THE QUESTION AND SOLUTION. WHAT YOU WILL DO IS TO INPUT THE SCRIPT IN MATLAB. PLEASE TAKE A SCREENSHOT OF THE SCRIPT AND COMMAND WINDOW.
![37. The electrical circuit shown consists of
resistors and voltage sources. Determine
11, 12, 13 and 14, using the mesh current
method based on Kirchhoff's voltage
law (see Sample Problem 3-4).
V₁=28 V₁ V₂ = 36 V, V3 = 42 V,
R₁ = 162
R₂ = 1022
R₂ = 62
R₁ = 122,
R₂ = 822
R6=1492
R₁=422 Rg=522.
Solution
V
R₁
@@@
R₂₁
R6
www
i4
V₁+|-
R₂
www
-V₂-R5i3-R7(i3-14) - R4(i3-i2) = 0
V₁-R₁i₁-R3(₁-1₂) = 0
-R₂i2-R4(12-13) — R6(1₂−14) — R3(1₂−1₁) = 0
V3-R6(14-12) - R7(14−13) -R8i4=0
The four equations can be rewritten in matrix form [A][x] = [B]:
13
R₂
www
WWRs
-(R₁ + R₂)
R3
0
0
Script file:
clear, clc
V1=28; V2=36; V3=42;
R1=16; R2=10; R3=6; R4=12;
R5=8; R6=14; R7=4; R8=5;
A=[-(R1+R3) R3 0 0
R₂
-(R₂ + R3+R4+R6)
R4
R6
R3 (R2+R3+R4+R6) R40
0 R4 (R4+R5+R7) R7
0 R6 R7 (R6+R7+R8)];
B= [-V1; 0; V2; -V3];
I=A\B
I =
Command Window:
>>
1.2136
-0.2168
-1.3656
1.4566
0
R₁
-(R₁ + R₂ + R₂)
R₁
0
R6
¹2
R₂
-(R6 + R7+ Rg) 14
0
V₂
-V3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc658d328-1e67-49d1-b35c-41264d39c7ad%2Fa0664e92-1da3-4353-b766-73c290a8d3d8%2Fw049pej_processed.png&w=3840&q=75)
Transcribed Image Text:37. The electrical circuit shown consists of
resistors and voltage sources. Determine
11, 12, 13 and 14, using the mesh current
method based on Kirchhoff's voltage
law (see Sample Problem 3-4).
V₁=28 V₁ V₂ = 36 V, V3 = 42 V,
R₁ = 162
R₂ = 1022
R₂ = 62
R₁ = 122,
R₂ = 822
R6=1492
R₁=422 Rg=522.
Solution
V
R₁
@@@
R₂₁
R6
www
i4
V₁+|-
R₂
www
-V₂-R5i3-R7(i3-14) - R4(i3-i2) = 0
V₁-R₁i₁-R3(₁-1₂) = 0
-R₂i2-R4(12-13) — R6(1₂−14) — R3(1₂−1₁) = 0
V3-R6(14-12) - R7(14−13) -R8i4=0
The four equations can be rewritten in matrix form [A][x] = [B]:
13
R₂
www
WWRs
-(R₁ + R₂)
R3
0
0
Script file:
clear, clc
V1=28; V2=36; V3=42;
R1=16; R2=10; R3=6; R4=12;
R5=8; R6=14; R7=4; R8=5;
A=[-(R1+R3) R3 0 0
R₂
-(R₂ + R3+R4+R6)
R4
R6
R3 (R2+R3+R4+R6) R40
0 R4 (R4+R5+R7) R7
0 R6 R7 (R6+R7+R8)];
B= [-V1; 0; V2; -V3];
I=A\B
I =
Command Window:
>>
1.2136
-0.2168
-1.3656
1.4566
0
R₁
-(R₁ + R₂ + R₂)
R₁
0
R6
¹2
R₂
-(R6 + R7+ Rg) 14
0
V₂
-V3
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