The problem is on the screen and the answers are on the paper. My question is, when comparing 41 and 43, why do we do 1-(y)^1/2 (circled in pink) in this one and not in number 41. Basically why don't we subtract the right function from the left function in 41, and how do I know when to do this when revolving about other lines? 39-44. Shell method about other lines Let R be the region bounded by y=x,x=1, and y= 0 Use t39. X=-240. X 141. X=242. y=143. y=-2 6.4.41 V = 2T0.(2-x)x² dx= 27(2x2- a) da2x315T%3D0.%3D2T3.40.6.4.42r1V = 27(1- y)(1- vT) dy = 27(1- Vỹ - y + y%/2) dy0.2y3/2y2127 y2y5/2!12.=2T 1.3.|%3D3156.4.431.2y5/2/ 4y3/2+ 2y,2V = 2T| (y + 2)(1 – Vỹ) dy = 27(y +2-y3/2 - 2y/2) dy = 2n%3D%3D0.0.3014.23T2.+2%3D2T3.15

Region is bounded by, y=x2 ; x=1; y=0 ----------------------------------------------- To get the…

Answered: 39-44. Shell method about other lines…

39-44. Shell method about other lines Let R be the region bounded by y=x2,x=1, and y=0. Use C 39. X=-2 40. X=1 41. X=2 42. y=1 43. y=-2

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter7: Analytic Trigonometry

Section7.6: The Inverse Trigonometric Functions

Problem 91E

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Question

The problem is on the screen and the answers are on the paper. My question is, when comparing 41 and 43, why do we do 1-(y)^1/2 (circled in pink) in this one and not in number 41. Basically why don't we subtract the right function from the left function in 41, and how do I know when to do this when revolving about other lines?