39–48. First Derivative Test a. Locate the critical points of f. b. Use the First Derivative Test to locate the local maximum and minimum values. c. Identify the absolute maximum and minimum values of the function on the given interval (when they exist). 39. f(x) = x² + 3 on [-3, 2] 40. f(x) = -x² – x + 2 on [-4, 4] %3D 41. f(x) = xV4 – x² on [-2, 2] 42. f(x) = 2x³ + 3x² – 12x + 1 on [-2, 4] 43. f(x) = -x³ + 9x on [-4, 3] %3D 44. f(x) = 2x5 – 5x4 – 10x3 + 4 on [-2, 4] %3D 45. f(x) = x2/3 (x – 5) on [-5, 5] x2 46. f(x) = 2 on [-4, 4] x² – 1 47. f(x) = VīlIn x on (0, *) 48. f(x) = tan x - r' on [-1, 11

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
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Chapter1: Functions
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39–48. First Derivative Test
a. Locate the critical points of f.
b. Use the First Derivative Test to locate the local maximum and
minimum values.
c. Identify the absolute maximum and minimum values of the function
on the given interval (when they exist).
39. f(x) = x² + 3 on [-3, 2]
40. f(x) = -x² – x + 2 on [-4, 4]
%3D
41. f(x) = xV4 – x² on [-2, 2]
42. f(x) = 2x³ + 3x² – 12x + 1 on [-2, 4]
43. f(x) = -x³ + 9x on [-4, 3]
%3D
44. f(x) = 2x5 – 5x4 – 10x3 + 4 on [-2, 4]
%3D
45. f(x) = x2/3 (x – 5) on [-5, 5]
x2
46. f(x) = 2 on [-4, 4]
x² – 1
47. f(x) = VīlIn x on (0, *)
48.
f(x) = tan x - r' on [-1, 11
Transcribed Image Text:39–48. First Derivative Test a. Locate the critical points of f. b. Use the First Derivative Test to locate the local maximum and minimum values. c. Identify the absolute maximum and minimum values of the function on the given interval (when they exist). 39. f(x) = x² + 3 on [-3, 2] 40. f(x) = -x² – x + 2 on [-4, 4] %3D 41. f(x) = xV4 – x² on [-2, 2] 42. f(x) = 2x³ + 3x² – 12x + 1 on [-2, 4] 43. f(x) = -x³ + 9x on [-4, 3] %3D 44. f(x) = 2x5 – 5x4 – 10x3 + 4 on [-2, 4] %3D 45. f(x) = x2/3 (x – 5) on [-5, 5] x2 46. f(x) = 2 on [-4, 4] x² – 1 47. f(x) = VīlIn x on (0, *) 48. f(x) = tan x - r' on [-1, 11
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