3n - 2" Determine whether the series > 4n converges or diverges. If it converges, find its sum. n=0 Select the correct choice below and, if necessary, fill in the answer box within your choice. The series converges because it is the difference between two geometric series, each with Ir| <1. The sum of the series is O A. (Type an integer or a simplified fraction.) O B. The series diverges because it is the difference between two geometric series, at least one with r2 1. 3n - 2" #0 or fails to exist. 4h Oc. The series diverges because lim n-00 3n - 2" = 0. The sum of the series is 4n The series converges because lim OD. n-00 (Type an integer or a simplified fraction.)

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter13: Sequences And Series
Section13.CR: Chapter Review
Problem 6CC
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3" - 2"
Determine whether the series >
converges or diverges. If it converges, find its sum.
4"
n = 0
Select the correct choice below and, if necessary, fill in the answer box within your choice.
The series converges because it is the difference between two geometric series, each with r<1. The sum of the series is
А.
(Type an integer or a simplified fraction.)
B. The series diverges because it is the difference between two geometric series, at least one with r 2 1.
3" - 2"
C. The series diverges because lim
+0 or fails to exist.
4"
3" - 2"
= 0. The sum of the series is
4n
The series converges because lim
(Type an integer or a simplified fraction.)
Transcribed Image Text:3" - 2" Determine whether the series > converges or diverges. If it converges, find its sum. 4" n = 0 Select the correct choice below and, if necessary, fill in the answer box within your choice. The series converges because it is the difference between two geometric series, each with r<1. The sum of the series is А. (Type an integer or a simplified fraction.) B. The series diverges because it is the difference between two geometric series, at least one with r 2 1. 3" - 2" C. The series diverges because lim +0 or fails to exist. 4" 3" - 2" = 0. The sum of the series is 4n The series converges because lim (Type an integer or a simplified fraction.)
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